QuestionAugust 3, 2025

Ohm's law is I=Vdiv R What's the voltage of the battery described? A circuit has one 10.0-ohm resistor. The current flowing through the circuit is 0.15 amps. So the battery in the circuit is a square -volt battery.

Ohm's law is I=Vdiv R What's the voltage of the battery described? A circuit has one 10.0-ohm resistor. The current flowing through the circuit is 0.15 amps. So the battery in the circuit is a square -volt battery.
Ohm's law is I=Vdiv R What's the voltage of the battery described?
A circuit has one 10.0-ohm resistor. The current flowing through the circuit is 0.15 amps. So the battery in the circuit
is a square  -volt battery.

Solution
4.6(297 votes)

Answer

1.5 volts Explanation 1. Identify the known values Resistance R = 10.0 \, \text{ohms}, Current I = 0.15 \, \text{amps}. 2. Apply Ohm's Law to find Voltage Use the formula **V = I \times R**. Substitute I = 0.15 and R = 10.0. 3. Calculate Voltage V = 0.15 \times 10.0 = 1.5 \, \text{volts}.

Explanation

1. Identify the known values<br /> Resistance $R = 10.0 \, \text{ohms}$, Current $I = 0.15 \, \text{amps}$.<br /><br />2. Apply Ohm's Law to find Voltage<br /> Use the formula **$V = I \times R$**. Substitute $I = 0.15$ and $R = 10.0$.<br /><br />3. Calculate Voltage<br /> $V = 0.15 \times 10.0 = 1.5 \, \text{volts}$.
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