QuestionJune 20, 2025

What volume will 5.87 moles of sulfur hexafluoride (SF_(6)) gas occupy if the temperature and pressure of the gas are 131 "C and 8.05 atm? and pressure of the gas are 131^circ C Round your answer to 3 significant digits. square L

What volume will 5.87 moles of sulfur hexafluoride (SF_(6)) gas occupy if the temperature and pressure of the gas are 131 "C and 8.05 atm? and pressure of the gas are 131^circ C Round your answer to 3 significant digits. square L
What volume will 5.87 moles of sulfur hexafluoride (SF_(6)) gas occupy if the temperature and pressure of the gas are 131 "C and 8.05 atm? and pressure of the gas are 131^circ C Round your answer to 3 significant digits. square L

Solution
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Answer

240 L Explanation 1. Convert Temperature to Kelvin T(K) = 131 + 273.15 = 404.15 \, K 2. Use Ideal Gas Law **PV = nRT** where P = 8.05 \, atm, n = 5.87 \, moles, R = 0.0821 \, \frac{L \cdot atm}{mol \cdot K}, and T = 404.15 \, K. 3. Solve for Volume V V = \frac{nRT}{P} = \frac{5.87 \times 0.0821 \times 404.15}{8.05} 4. Calculate the Volume V \approx 240.0 \, L

Explanation

1. Convert Temperature to Kelvin<br /> $T(K) = 131 + 273.15 = 404.15 \, K$<br /><br />2. Use Ideal Gas Law<br /> **$PV = nRT$** where $P = 8.05 \, atm$, $n = 5.87 \, moles$, $R = 0.0821 \, \frac{L \cdot atm}{mol \cdot K}$, and $T = 404.15 \, K$.<br /><br />3. Solve for Volume $V$<br /> $V = \frac{nRT}{P} = \frac{5.87 \times 0.0821 \times 404.15}{8.05}$<br /><br />4. Calculate the Volume<br /> $V \approx 240.0 \, L$
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