QuestionMay 8, 2025

How many grams of sodium metal are needed to make 29.3 grams of sodium chloride? Given the reaction: 2Na+Cl_(2)arrow 2NaCl 46.0 23.0 not enough information 5.75 11.5

How many grams of sodium metal are needed to make 29.3 grams of sodium chloride? Given the reaction: 2Na+Cl_(2)arrow 2NaCl 46.0 23.0 not enough information 5.75 11.5
How many grams of sodium metal are needed to make 29.3 grams of sodium chloride?
Given the reaction: 2Na+Cl_(2)arrow 2NaCl
46.0
23.0
not enough information
5.75
11.5

Solution
4.2(187 votes)

Answer

11.5 Explanation 1. Calculate moles of NaCl Use the formula n = \frac{m}{M}, where m is mass and M is molar mass. Molar mass of NaCl is 58.5 g/mol. So, n = \frac{29.3}{58.5} \approx 0.5 moles. 2. Determine moles of Na needed From the balanced equation, 2 moles of Na produce 2 moles of NaCl. Therefore, 0.5 moles of NaCl require 0.5 moles of Na. 3. Calculate mass of Na needed Use the formula m = n \times M. Molar mass of Na is 23.0 g/mol. So, m = 0.5 \times 23.0 = 11.5 grams.

Explanation

1. Calculate moles of NaCl<br /> Use the formula $n = \frac{m}{M}$, where $m$ is mass and $M$ is molar mass. Molar mass of NaCl is 58.5 g/mol. So, $n = \frac{29.3}{58.5} \approx 0.5$ moles.<br />2. Determine moles of Na needed<br /> From the balanced equation, 2 moles of Na produce 2 moles of NaCl. Therefore, 0.5 moles of NaCl require 0.5 moles of Na.<br />3. Calculate mass of Na needed<br /> Use the formula $m = n \times M$. Molar mass of Na is 23.0 g/mol. So, $m = 0.5 \times 23.0 = 11.5$ grams.
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