QuestionJune 21, 2025

Use the following data to calculate the enthalpy of reaction (Delta H_(rxn)) of the formation of strontium chloride SrCl_(2) The enthalpy of sublimation of strontium=+164kJ/mol First ionization energy for strontium=+549kJ/mol Second ionization energy for strontium=+1064kJ/mol The enthalpy of dissociation of chlorine, Cl_(2)=+243kJ/mol The electron affinity of chlorine, Cl=-349kJ/mol Lattice energy of strontium chloride=-2150kJ/mol -4868kJ/mol -828kJ/mol -1377kJ/mol -479kJ/mol

Use the following data to calculate the enthalpy of reaction (Delta H_(rxn)) of the formation of strontium chloride SrCl_(2) The enthalpy of sublimation of strontium=+164kJ/mol First ionization energy for strontium=+549kJ/mol Second ionization energy for strontium=+1064kJ/mol The enthalpy of dissociation of chlorine, Cl_(2)=+243kJ/mol The electron affinity of chlorine, Cl=-349kJ/mol Lattice energy of strontium chloride=-2150kJ/mol -4868kJ/mol -828kJ/mol -1377kJ/mol -479kJ/mol
Use the following data to calculate the enthalpy of reaction (Delta H_(rxn)) of the formation of
strontium chloride SrCl_(2)
The enthalpy of sublimation of strontium=+164kJ/mol
First ionization energy for strontium=+549kJ/mol
Second ionization energy for strontium=+1064kJ/mol
The enthalpy of dissociation of chlorine, Cl_(2)=+243kJ/mol
The electron affinity of chlorine, Cl=-349kJ/mol
Lattice energy of strontium chloride=-2150kJ/mol
-4868kJ/mol
-828kJ/mol
-1377kJ/mol
-479kJ/mol

Solution
4.5(206 votes)

Answer

-600.5 \text{ kJ/mol} Explanation 1. Calculate the energy required for strontium Sum sublimation, first and second ionization energies: 164 + 549 + 1064 = 1777 \text{ kJ/mol} 2. Calculate the energy required for chlorine Dissociation energy divided by 2 (for one mole of Cl atoms) plus electron affinity: \frac{243}{2} - 349 = -227.5 \text{ kJ/mol} 3. Calculate total energy change Add lattice energy to previous results: 1777 - 227.5 - 2150 = -600.5 \text{ kJ/mol}

Explanation

1. Calculate the energy required for strontium<br /> Sum sublimation, first and second ionization energies: $164 + 549 + 1064 = 1777 \text{ kJ/mol}$<br />2. Calculate the energy required for chlorine<br /> Dissociation energy divided by 2 (for one mole of Cl atoms) plus electron affinity: $\frac{243}{2} - 349 = -227.5 \text{ kJ/mol}$<br />3. Calculate total energy change<br /> Add lattice energy to previous results: $1777 - 227.5 - 2150 = -600.5 \text{ kJ/mol}$
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