QuestionMay 1, 2025

8. 30 g of Rb_(2)C_(2)O_(4) are dissolved in 0.39 L of water.What is the concentration of this solution in molarity?

8. 30 g of Rb_(2)C_(2)O_(4) are dissolved in 0.39 L of water.What is the concentration of this solution in molarity?
8. 30 g of Rb_(2)C_(2)O_(4) are dissolved in 0.39 L of water.What is the concentration of this solution in molarity?

Solution
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Answer

0.341 M Explanation 1. Calculate moles of Rb_{2}C_{2}O_{4} Molar mass of Rb_{2}C_{2}O_{4} is (2 \times 85.47) + (2 \times 12.01) + (4 \times 16.00) = 225.56 g/mol. Moles = \frac{30 \text{ g}}{225.56 \text{ g/mol}} = 0.133 mol. 2. Calculate molarity **Molarity (M) = \frac{\text{moles of solute}}{\text{liters of solution}}**. Molarity = \frac{0.133 \text{ mol}}{0.39 \text{ L}} = 0.341 M.

Explanation

1. Calculate moles of $Rb_{2}C_{2}O_{4}$<br /> Molar mass of $Rb_{2}C_{2}O_{4}$ is $(2 \times 85.47) + (2 \times 12.01) + (4 \times 16.00) = 225.56$ g/mol. Moles = $\frac{30 \text{ g}}{225.56 \text{ g/mol}} = 0.133$ mol.<br />2. Calculate molarity<br /> **Molarity (M) = $\frac{\text{moles of solute}}{\text{liters of solution}}$**. Molarity = $\frac{0.133 \text{ mol}}{0.39 \text{ L}} = 0.341$ M.
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