Find the value of the discriminant for the equation, 3x^2=6x-2 Then.determine the number and type of roots. Since the discriminant is less than 0 and is a perfect square , the two roots are imaginary. Since the discriminant is equal to 0 and is a perfect square . the 1 root is real and rational. Since the discriminant is greater than 0 and is a perfect square, the two roots are real and rational. Since the discriminant is greater than 0 and

Identify the equations from that list that have $x=3$ as a solution. (Select all that apply.) $6x-1=17$ $x^{2}-9$ $4x^{2}+10=46$ $2x-3=x^{2}-6$ none of these

Instructions: Solve the quadratic equation by factoring and using the Zero Product Property. $(x+7)(x+5)=0$ Step 1: Apply the Zero Product Property. $x+7=0$ OR $x+5=0$ Step 2: Solve. $x=\square $ OR $x=\square $

En la función $y=4x^{2}-4x-3$ las coordenadas de su vértice son: $(2,-4)$ $(\frac {1}{2},-4)$ $(2,4)$ $(-\frac {1}{2},-4)$ $(-\frac {1}{2},4)$

If $\overline {CF}$ is an altitude of $\Delta CDE$ find $m\angle CEF$ if $m\angle CFE=(3x+36)^{\circ }$ and $m\angle FCE=(2x+18)^{\circ }$ A. $18^{\circ }$ B. $36^{\circ }$ C. $54^{\circ }$ D. $90^{\circ }$

Use radical notation to write the expression. Simplify.if possible. $625^{1/4}$ Select the correct choice below and, if necessary,fill in the answer box to complete your choice. A. $625^{1/4}=\square $ (Simplify your answer. Type an exact answer, using radicals as needed.) B. The answer is not a real number.

Solve the equation. $6=\frac {x}{5}$ $x=\square $

How many solutions does the equation $x^{2}+\frac {1}{2}x+5=0$ have? (A) No real solution (B) 1 real solution (C) 2 rational solutions (D) 2 irrational solutions (E) Cannot be determined

Question Rewrite in simplest terms: $-8(-3p-1)-8p$ Answer Attemptiout of 2 $\square $

Solve: $x^{2}-4x+13=0$ Identify the type of roots

Solve $4-x=-8$ A. $x=12$ B. $x=4$ C. $x=-4$ D. $x=-12$