QuestionAugust 11, 2025

Write the equilibrium constant expression for K_(c) for the following process. 2CO_(2)(g)leftharpoons 2CO(g)+O_(2)(g) K_(c)= square

Write the equilibrium constant expression for K_(c) for the following process. 2CO_(2)(g)leftharpoons 2CO(g)+O_(2)(g) K_(c)= square
Write the equilibrium constant expression for K_(c) for the following process.
2CO_(2)(g)leftharpoons 2CO(g)+O_(2)(g)
K_(c)= square

Solution
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Answer

K_c = \frac CO]^2[O_2 CO_2]^2} Explanation 1. Identify the reaction components The reaction is 2CO_{2}(g) \rightleftharpoons 2CO(g) + O_{2}(g). 2. Write the equilibrium constant expression For a general reaction aA + bB \rightleftharpoons cC + dD, the equilibrium constant expression is **K_c = \frac C]^c[D]^d} A]^a[B]^b}**. 3. Apply to the given reaction Substitute the components into the formula: K_c = \frac CO]^2[O_2 CO_2]^2}.

Explanation

1. Identify the reaction components<br /> The reaction is $2CO_{2}(g) \rightleftharpoons 2CO(g) + O_{2}(g)$.<br /><br />2. Write the equilibrium constant expression<br /> For a general reaction $aA + bB \rightleftharpoons cC + dD$, the equilibrium constant expression is **$K_c = \frac{[C]^c[D]^d}{[A]^a[B]^b}$**. <br /><br />3. Apply to the given reaction<br /> Substitute the components into the formula: $K_c = \frac{[CO]^2[O_2]}{[CO_2]^2}$.
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