QuestionJuly 18, 2025

4. In a mixture of hydrogen (H_(2)) and argon (Ar) gas, 15% of the total gas pressure is exerted by hydrogen. If the total pressure is 60 .0 atm, what pressure does the hydrogen exert? (Answer=9.0atm)

4. In a mixture of hydrogen (H_(2)) and argon (Ar) gas, 15% of the total gas pressure is exerted by hydrogen. If the total pressure is 60 .0 atm, what pressure does the hydrogen exert? (Answer=9.0atm)
4. In a mixture of hydrogen (H_(2)) and argon (Ar) gas, 15%  of the total gas pressure is exerted by hydrogen. If the
total pressure is 60 .0 atm, what pressure does the hydrogen exert? (Answer=9.0atm)

Solution
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Answer

9.0 atm Explanation 1. Calculate the pressure exerted by hydrogen Use the formula for partial pressure: P_{\text{H}_2} = \text{Total Pressure} \times \text{Percentage of } H_2. Here, P_{\text{H}_2} = 60.0 \, \text{atm} \times 0.15.

Explanation

1. Calculate the pressure exerted by hydrogen<br /> Use the formula for partial pressure: $P_{\text{H}_2} = \text{Total Pressure} \times \text{Percentage of } H_2$. Here, $P_{\text{H}_2} = 60.0 \, \text{atm} \times 0.15$.
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