QuestionAugust 27, 2025

A survey finds that 48% of people identify themselves as fans of professional football, 12% as fans of car racing. and 9% as fans of both professional football and car racing. Let event F be choosing a person who is a fan of professional football and let event C be choosing a person who is a fan of car racing. Which statements are true?Select three options. P(Fvert C)=0.75 D P(Cvert F)=0.25 P(Ccap F)=0.09 D P(Ccap F)=P(Fcap C) P(Cvert F)=P(Fvert C)

A survey finds that 48% of people identify themselves as fans of professional football, 12% as fans of car racing. and 9% as fans of both professional football and car racing. Let event F be choosing a person who is a fan of professional football and let event C be choosing a person who is a fan of car racing. Which statements are true?Select three options. P(Fvert C)=0.75 D P(Cvert F)=0.25 P(Ccap F)=0.09 D P(Ccap F)=P(Fcap C) P(Cvert F)=P(Fvert C)
A survey finds that 48%  of people identify themselves as
fans of professional football, 12%  as fans of car racing.
and 9%  as fans of both professional football and car
racing. Let event F be choosing a person who is a fan of
professional football and let event C be choosing a
person who is a fan of car racing.
Which statements are true?Select three options.
P(Fvert C)=0.75
D P(Cvert F)=0.25
P(Ccap F)=0.09
D P(Ccap F)=P(Fcap C)
P(Cvert F)=P(Fvert C)

Solution
4.7(260 votes)

Answer

P(F\vert C)=0.75, P(C\cap F)=0.09, P(C\cap F)=P(F\cap C) Explanation 1. Calculate P(F \cap C) Given directly as 0.09. 2. Verify P(C \cap F) = P(F \cap C) Intersection is commutative, so P(C \cap F) = P(F \cap C) = 0.09. 3. Calculate P(F \vert C) **Formula:** P(F \vert C) = \frac{P(F \cap C)}{P(C)} = \frac{0.09}{0.12} = 0.75. 4. Calculate P(C \vert F) **Formula:** P(C \vert F) = \frac{P(C \cap F)}{P(F)} = \frac{0.09}{0.48} = 0.1875. 5. Compare P(C \vert F) and P(F \vert C) P(C \vert F) = 0.1875 \neq P(F \vert C) = 0.75.

Explanation

1. Calculate $P(F \cap C)$<br /> Given directly as $0.09$.<br /><br />2. Verify $P(C \cap F) = P(F \cap C)$<br /> Intersection is commutative, so $P(C \cap F) = P(F \cap C) = 0.09$.<br /><br />3. Calculate $P(F \vert C)$<br /> **Formula:** $P(F \vert C) = \frac{P(F \cap C)}{P(C)} = \frac{0.09}{0.12} = 0.75$.<br /><br />4. Calculate $P(C \vert F)$<br /> **Formula:** $P(C \vert F) = \frac{P(C \cap F)}{P(F)} = \frac{0.09}{0.48} = 0.1875$.<br /><br />5. Compare $P(C \vert F)$ and $P(F \vert C)$<br /> $P(C \vert F) = 0.1875 \neq P(F \vert C) = 0.75$.
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