QuestionDecember 13, 2025

4. If an effort force of 30 pounds is applied through a distance of 1.5 feet (d_(e)) in a second class lever, how far will the lever lift the load if the distance from the fulcrum to the effort force is 5 feet and the distance from the fulcrum to the load is 3.5 feet?

4. If an effort force of 30 pounds is applied through a distance of 1.5 feet (d_(e)) in a second class lever, how far will the lever lift the load if the distance from the fulcrum to the effort force is 5 feet and the distance from the fulcrum to the load is 3.5 feet?
4. If an effort force of 30 pounds is applied through a distance of 1.5 feet (d_(e))
in a second class lever, how far will the lever lift the load if the distance
from the fulcrum to the effort force is 5 feet and the distance from the
fulcrum to the load is 3.5 feet?

Solution
4.5(227 votes)

Answer

1.05 feet Explanation 1. Calculate Mechanical Advantage (MA) MA = \frac{d_{effort}}{d_{load}} = \frac{5}{3.5} = 1.4286 2. Relate Effort Distance to Load Distance \text{Load distance} = \frac{\text{Effort distance}}{MA} = \frac{1.5}{1.4286} = 1.05 feet

Explanation

1. Calculate Mechanical Advantage (MA)<br /> $MA = \frac{d_{effort}}{d_{load}} = \frac{5}{3.5} = 1.4286$<br />2. Relate Effort Distance to Load Distance<br /> $\text{Load distance} = \frac{\text{Effort distance}}{MA} = \frac{1.5}{1.4286} = 1.05$ feet
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