QuestionMay 7, 2025

(05.01 MC) How many atoms of K are present in 19549 grams of K? 3.0110times 10^24 6.0220times 10^24 1.1772times 10^26 4.5797times 10^27

(05.01 MC) How many atoms of K are present in 19549 grams of K? 3.0110times 10^24 6.0220times 10^24 1.1772times 10^26 4.5797times 10^27
(05.01 MC) How many atoms of K are present in 19549 grams of K? 3.0110times 10^24 6.0220times 10^24 1.1772times 10^26 4.5797times 10^27

Solution
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Answer

3.0110\times 10^{24} Explanation 1. Calculate moles of K Use the formula: \text{moles} = \frac{\text{mass}}{\text{molar mass}}. The molar mass of K is approximately 39.10 g/mol. Thus, \text{moles of K} = \frac{19549}{39.10}. 2. Convert moles to atoms Use Avogadro's number: 6.022 \times 10^{23} atoms/mol. Multiply moles by Avogadro's number to find atoms: \text{atoms of K} = \text{moles of K} \times 6.022 \times 10^{23}.

Explanation

1. Calculate moles of K<br /> Use the formula: $\text{moles} = \frac{\text{mass}}{\text{molar mass}}$. The molar mass of K is approximately 39.10 g/mol. Thus, $\text{moles of K} = \frac{19549}{39.10}$.<br /><br />2. Convert moles to atoms<br /> Use Avogadro's number: $6.022 \times 10^{23}$ atoms/mol. Multiply moles by Avogadro's number to find atoms: $\text{atoms of K} = \text{moles of K} \times 6.022 \times 10^{23}$.
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