QuestionAugust 4, 2025

The combustion of glucose (C_(6)H_(12)O_(6)) in oxygen produces carbon dioxide and water. Which choice correctly expresses the average rate of reaction in terms of the change in concentration of carbon dioxide? C_(6)H_(12)O_(6)(s)+6O_(2)(g)arrow 6CO_(2)(g)+6H_(2)O(l) Rate=(1)/(6)(Delta [CO_(2)])/(Delta t) Rate=-6(Delta [CO_(2)])/(Delta t) Rate=-(1)/(6)(Delta [CO_(2)])/(Delta t) Rate=6(Delta [CO_(2)])/(Delta t)

The combustion of glucose (C_(6)H_(12)O_(6)) in oxygen produces carbon dioxide and water. Which choice correctly expresses the average rate of reaction in terms of the change in concentration of carbon dioxide? C_(6)H_(12)O_(6)(s)+6O_(2)(g)arrow 6CO_(2)(g)+6H_(2)O(l) Rate=(1)/(6)(Delta [CO_(2)])/(Delta t) Rate=-6(Delta [CO_(2)])/(Delta t) Rate=-(1)/(6)(Delta [CO_(2)])/(Delta t) Rate=6(Delta [CO_(2)])/(Delta t)
The combustion of glucose (C_(6)H_(12)O_(6)) in oxygen produces carbon dioxide and water. Which choice correctly
expresses the average rate of reaction in terms of the change in concentration of carbon dioxide?
C_(6)H_(12)O_(6)(s)+6O_(2)(g)arrow 6CO_(2)(g)+6H_(2)O(l)
Rate=(1)/(6)(Delta [CO_(2)])/(Delta t)
Rate=-6(Delta [CO_(2)])/(Delta t)
Rate=-(1)/(6)(Delta [CO_(2)])/(Delta t)
Rate=6(Delta [CO_(2)])/(Delta t)

Solution
4.4(178 votes)

Answer

Rate=\frac {1}{6}\frac {\Delta [CO_{2}]}{\Delta t} Explanation 1. Identify the stoichiometry The balanced equation shows 6 moles of CO_2 are produced per mole of glucose. 2. Apply rate formula for products For a product, the average rate is given by **Rate = \frac{1}{\text{stoichiometric coefficient}} \frac{\Delta [Product]}{\Delta t}**. 3. Calculate rate for CO_2 Using the stoichiometric coefficient of 6 for CO_2, the rate is \frac{1}{6} \frac{\Delta [CO_2]}{\Delta t}.

Explanation

1. Identify the stoichiometry<br /> The balanced equation shows 6 moles of $CO_2$ are produced per mole of glucose.<br /><br />2. Apply rate formula for products<br /> For a product, the average rate is given by **$Rate = \frac{1}{\text{stoichiometric coefficient}} \frac{\Delta [Product]}{\Delta t}$**.<br /><br />3. Calculate rate for $CO_2$<br /> Using the stoichiometric coefficient of 6 for $CO_2$, the rate is $\frac{1}{6} \frac{\Delta [CO_2]}{\Delta t}$.
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