QuestionJuly 28, 2025

Select the pair that has the larger atom or ion listed first. Br^-,Se^2- S,S^2- Cl,Cl^- F^-,Ne P,P^3-

Select the pair that has the larger atom or ion listed first. Br^-,Se^2- S,S^2- Cl,Cl^- F^-,Ne P,P^3-
Select the pair that has the larger atom or ion listed first.
Br^-,Se^2-
S,S^2-
Cl,Cl^-
F^-,Ne
P,P^3-

Solution
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Answer

Se^{2-}, S^{2-}, Cl^{-}, F^{-}, P^{3-} Explanation 1. Compare atomic and ionic sizes Anions are generally larger than their neutral atoms due to increased electron-electron repulsion. Compare each pair based on this principle. 2. Analyze each pair - Br^{-} vs Se^{2-}: Se^{2-} is larger because it has more electrons added compared to Br^{-}. - S vs S^{2-}: S^{2-} is larger due to the addition of electrons. - Cl vs Cl^{-}: Cl^{-} is larger due to the addition of an electron. - F^{-} vs Ne: F^{-} is larger because anions are larger than neutral atoms. - P vs P^{3-}: P^{3-} is larger due to the addition of electrons.

Explanation

1. Compare atomic and ionic sizes<br /> Anions are generally larger than their neutral atoms due to increased electron-electron repulsion. Compare each pair based on this principle.<br /><br />2. Analyze each pair<br /> <br />- $Br^{-}$ vs $Se^{2-}$: $Se^{2-}$ is larger because it has more electrons added compared to $Br^{-}$.<br />- $S$ vs $S^{2-}$: $S^{2-}$ is larger due to the addition of electrons.<br />- $Cl$ vs $Cl^{-}$: $Cl^{-}$ is larger due to the addition of an electron.<br />- $F^{-}$ vs $Ne$: $F^{-}$ is larger because anions are larger than neutral atoms.<br />- $P$ vs $P^{3-}$: $P^{3-}$ is larger due to the addition of electrons.
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