QuestionJune 26, 2025

Water is placed in an ice cube tray and placed in the freezer, tuning it into ice cubes. If water is the system, what will the heat and work values be for the surroundings? a q=-,w=+ b q=+,w=+ C. q=-,w=- d q=+,w=-

Water is placed in an ice cube tray and placed in the freezer, tuning it into ice cubes. If water is the system, what will the heat and work values be for the surroundings? a q=-,w=+ b q=+,w=+ C. q=-,w=- d q=+,w=-
Water is placed in an ice cube tray and placed in the freezer, tuning it into ice cubes. If water is
the system, what will the heat and work values be for the surroundings?
a
q=-,w=+
b
q=+,w=+
C.
q=-,w=-
d
q=+,w=-

Solution
4.6(128 votes)

Answer

a q=-,w=+ Explanation 1. Identify the process Freezing water is an exothermic process where heat is released to the surroundings. 2. Determine heat flow (q) Since heat is released, q for the surroundings is positive (q=+). 3. Determine work done (w) No work is done on or by the system as volume change is negligible, so w=0. However, in thermodynamics, if no work is done, it can be considered as w=- for the surroundings.

Explanation

1. Identify the process<br /> Freezing water is an exothermic process where heat is released to the surroundings.<br />2. Determine heat flow ($q$)<br /> Since heat is released, $q$ for the surroundings is positive ($q=+$).<br />3. Determine work done ($w$)<br /> No work is done on or by the system as volume change is negligible, so $w=0$. However, in thermodynamics, if no work is done, it can be considered as $w=-$ for the surroundings.
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