QuestionMay 14, 2025

7. A chemist has 3.45times 10^22 molecules of P_(2)O_(5) How many grams of P_(2)O_(5) does the chemist have?

7. A chemist has 3.45times 10^22 molecules of P_(2)O_(5) How many grams of P_(2)O_(5) does the chemist have?
7. A chemist has 3.45times 10^22 molecules of P_(2)O_(5) How many grams of P_(2)O_(5) does the chemist have?

Solution
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Answer

8.13 grams Explanation 1. Calculate moles of P_{2}O_{5} Use the formula: \text{moles} = \frac{\text{number of molecules}}{6.022 \times 10^{23}}. Moles of P_{2}O_{5} = \frac{3.45 \times 10^{22}}{6.022 \times 10^{23}} = 0.0573 moles. 2. Calculate molar mass of P_{2}O_{5} Molar mass of P_{2}O_{5} = 2 \times 30.97 + 5 \times 16.00 = 141.94 g/mol. 3. Calculate grams of P_{2}O_{5} Use the formula: \text{grams} = \text{moles} \times \text{molar mass}. Grams of P_{2}O_{5} = 0.0573 \times 141.94 = 8.13 grams.

Explanation

1. Calculate moles of $P_{2}O_{5}$<br /> Use the formula: $\text{moles} = \frac{\text{number of molecules}}{6.022 \times 10^{23}}$. <br /> Moles of $P_{2}O_{5} = \frac{3.45 \times 10^{22}}{6.022 \times 10^{23}} = 0.0573$ moles.<br /><br />2. Calculate molar mass of $P_{2}O_{5}$<br /> Molar mass of $P_{2}O_{5} = 2 \times 30.97 + 5 \times 16.00 = 141.94$ g/mol.<br /><br />3. Calculate grams of $P_{2}O_{5}$<br /> Use the formula: $\text{grams} = \text{moles} \times \text{molar mass}$.<br /> Grams of $P_{2}O_{5} = 0.0573 \times 141.94 = 8.13$ grams.
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