QuestionAugust 15, 2025

C_(4)H_(10)+O_(2)arrow CO_(2)+H_(2)O A 17C_(4)H_(10)+3O_(2)arrow 7CO_(2)+4H_(2)O B 2C_(4)H_(10)+13O_(2)arrow 8CO_(2)+10H_(2)O C 3C_(4)H_(10)+5O_(2)arrow 8CO_(2)+4H_(2)O D 5C_(4)H_(10)+2O_(2)arrow 14CO_(2)+6H_(2)O

C_(4)H_(10)+O_(2)arrow CO_(2)+H_(2)O A 17C_(4)H_(10)+3O_(2)arrow 7CO_(2)+4H_(2)O B 2C_(4)H_(10)+13O_(2)arrow 8CO_(2)+10H_(2)O C 3C_(4)H_(10)+5O_(2)arrow 8CO_(2)+4H_(2)O D 5C_(4)H_(10)+2O_(2)arrow 14CO_(2)+6H_(2)O
C_(4)H_(10)+O_(2)arrow CO_(2)+H_(2)O
A 17C_(4)H_(10)+3O_(2)arrow 7CO_(2)+4H_(2)O
B 2C_(4)H_(10)+13O_(2)arrow 8CO_(2)+10H_(2)O
C 3C_(4)H_(10)+5O_(2)arrow 8CO_(2)+4H_(2)O
D 5C_(4)H_(10)+2O_(2)arrow 14CO_(2)+6H_(2)O

Solution
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Answer

B 2C_{4}H_{10}+13O_{2}\rightarrow 8CO_{2}+10H_{2}O Explanation 1. Identify the correct balanced equation Balance the number of atoms for each element on both sides. For C_4H_{10}, balance carbon, hydrogen, and oxygen. 2. Check Option B 2C_{4}H_{10}+13O_{2}\rightarrow 8CO_{2}+10H_{2}O: - Carbon: 2 \times 4 = 8 (LHS) and 8 (RHS) - Hydrogen: 2 \times 10 = 20 (LHS) and 10 \times 2 = 20 (RHS) - Oxygen: 13 \times 2 = 26 (LHS) and 8 \times 2 + 10 = 26 (RHS)

Explanation

1. Identify the correct balanced equation<br /> Balance the number of atoms for each element on both sides. For $C_4H_{10}$, balance carbon, hydrogen, and oxygen.<br /><br />2. Check Option B<br /> $2C_{4}H_{10}+13O_{2}\rightarrow 8CO_{2}+10H_{2}O$: <br />- Carbon: $2 \times 4 = 8$ (LHS) and $8$ (RHS)<br />- Hydrogen: $2 \times 10 = 20$ (LHS) and $10 \times 2 = 20$ (RHS)<br />- Oxygen: $13 \times 2 = 26$ (LHS) and $8 \times 2 + 10 = 26$ (RHS)
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