QuestionAugust 27, 2025

17 Consider the system of equations below. 3x+2y=1 2y+z=2 2x-2z=-6 What is the value of x? (1) 1 (3) -4 (2) -1 (4) 4

17 Consider the system of equations below. 3x+2y=1 2y+z=2 2x-2z=-6 What is the value of x? (1) 1 (3) -4 (2) -1 (4) 4
17 Consider the system of equations below.
3x+2y=1
2y+z=2
2x-2z=-6
What is the value of x?
(1) 1
(3) -4
(2) -1
(4) 4

Solution
4.7(267 votes)

Answer

1 Explanation 1. Express z in terms of x From 2x - 2z = -6, solve for z: z = x + 3. 2. Substitute z into the second equation Replace z in 2y + z = 2 with x + 3: 2y + (x + 3) = 2. Simplify to 2y + x = -1. 3. Solve the system of equations Use 3x + 2y = 1 and 2y + x = -1. Multiply the second equation by 3: 3(2y + x = -1) gives 3x + 6y = -3. 4. Eliminate x and solve for y Subtract 3x + 2y = 1 from 3x + 6y = -3: (3x + 6y) - (3x + 2y) = -3 - 1. This simplifies to 4y = -4, so y = -1. 5. Substitute y back to find x Use 2y + x = -1 with y = -1: 2(-1) + x = -1. Solve for x: x = -1 + 2 = 1.

Explanation

1. Express $z$ in terms of $x$<br /> From $2x - 2z = -6$, solve for $z$: $z = x + 3$.<br />2. Substitute $z$ into the second equation<br /> Replace $z$ in $2y + z = 2$ with $x + 3$: $2y + (x + 3) = 2$. Simplify to $2y + x = -1$.<br />3. Solve the system of equations<br /> Use $3x + 2y = 1$ and $2y + x = -1$. Multiply the second equation by 3: $3(2y + x = -1)$ gives $3x + 6y = -3$.<br />4. Eliminate $x$ and solve for $y$<br /> Subtract $3x + 2y = 1$ from $3x + 6y = -3$: $(3x + 6y) - (3x + 2y) = -3 - 1$. This simplifies to $4y = -4$, so $y = -1$.<br />5. Substitute $y$ back to find $x$<br /> Use $2y + x = -1$ with $y = -1$: $2(-1) + x = -1$. Solve for $x$: $x = -1 + 2 = 1$.
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