QuestionAugust 18, 2025

Which of the following is an oxidation-reduction reaction? Fe_(2)O_(3)+3COarrow 2Fe+3CO_(2) CuSO_(4)+2NaOHarrow Cu(OH)_(2)+Na_(2)SO_(4) 2NaOH+H_(2)CO_(3)arrow Na_(2)CO_(3)+2NaOH Pb(NO_(3))_(2)+Na_(2)SO_(4)arrow 2NaNO_(3)+PbSO_(4)

Which of the following is an oxidation-reduction reaction? Fe_(2)O_(3)+3COarrow 2Fe+3CO_(2) CuSO_(4)+2NaOHarrow Cu(OH)_(2)+Na_(2)SO_(4) 2NaOH+H_(2)CO_(3)arrow Na_(2)CO_(3)+2NaOH Pb(NO_(3))_(2)+Na_(2)SO_(4)arrow 2NaNO_(3)+PbSO_(4)
Which of the following is an oxidation-reduction reaction?
Fe_(2)O_(3)+3COarrow 2Fe+3CO_(2)
CuSO_(4)+2NaOHarrow Cu(OH)_(2)+Na_(2)SO_(4)
2NaOH+H_(2)CO_(3)arrow Na_(2)CO_(3)+2NaOH
Pb(NO_(3))_(2)+Na_(2)SO_(4)arrow 2NaNO_(3)+PbSO_(4)

Solution
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Answer

\( \mathrm{Fe}_{2} \mathrm{O}_{3}+3 \mathrm{CO} \longrightarrow 2 \mathrm{Fe}+3 \mathrm{CO}_{2} \) Explanation 1. Identify oxidation-reduction reaction Oxidation-reduction reactions involve the transfer of electrons, where one species is oxidized and another is reduced. Look for changes in oxidation states. 2. Analyze each reaction 1. \mathrm{Fe}_{2} \mathrm{O}_{3}+3 \mathrm{CO} \longrightarrow 2 \mathrm{Fe}+3 \mathrm{CO}_{2}: Fe goes from +3 to 0 (reduction), C goes from +2 to +4 (oxidation). 2. \mathrm{CuSO}_{4}+2 \mathrm{NaOH} \longrightarrow \mathrm{Cu}(\mathrm{OH})_{2}+\mathrm{Na}_{2} \mathrm{SO}_{4}: No change in oxidation states. 3. 2 \mathrm{NaOH}+\mathrm{H}_{2} \mathrm{CO}_{3} \longrightarrow \mathrm{Na}_{2} \mathrm{CO}_{3}+2 \mathrm{NaOH}: No change in oxidation states. 4. \mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}+\mathrm{Na}_{2} \mathrm{SO}_{4} \longrightarrow 2 \mathrm{NaNO}_{3}+\mathrm{PbSO}_{4}: No change in oxidation states.

Explanation

1. Identify oxidation-reduction reaction<br /> Oxidation-reduction reactions involve the transfer of electrons, where one species is oxidized and another is reduced. Look for changes in oxidation states.<br /><br />2. Analyze each reaction<br /> 1. $\mathrm{Fe}_{2} \mathrm{O}_{3}+3 \mathrm{CO} \longrightarrow 2 \mathrm{Fe}+3 \mathrm{CO}_{2}$: Fe goes from +3 to 0 (reduction), C goes from +2 to +4 (oxidation).<br /> 2. $\mathrm{CuSO}_{4}+2 \mathrm{NaOH} \longrightarrow \mathrm{Cu}(\mathrm{OH})_{2}+\mathrm{Na}_{2} \mathrm{SO}_{4}$: No change in oxidation states.<br /> 3. $2 \mathrm{NaOH}+\mathrm{H}_{2} \mathrm{CO}_{3} \longrightarrow \mathrm{Na}_{2} \mathrm{CO}_{3}+2 \mathrm{NaOH}$: No change in oxidation states.<br /> 4. $\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}+\mathrm{Na}_{2} \mathrm{SO}_{4} \longrightarrow 2 \mathrm{NaNO}_{3}+\mathrm{PbSO}_{4}$: No change in oxidation states.
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