QuestionMay 8, 2025

2. A student mixed 4.00 mL of 0.0120 M Pb(NO_(3))_(2) with 4.00 mL of 0.0300 M KI and 2.00 mL of 0.20MKNO_(3) and observed the formation of a yellow precipitate. (0.5pts) a. What is the molecular formula of the precipitate?

2. A student mixed 4.00 mL of 0.0120 M Pb(NO_(3))_(2) with 4.00 mL of 0.0300 M KI and 2.00 mL of 0.20MKNO_(3) and observed the formation of a yellow precipitate. (0.5pts) a. What is the molecular formula of the precipitate?
2. A student mixed 4.00 mL of 0.0120 M Pb(NO_(3))_(2) with 4.00 mL of 0.0300 M KI and 2.00 mL of 0.20MKNO_(3) and observed the formation of a yellow
precipitate.
(0.5pts)
a. What is the molecular formula of the precipitate?

Solution
4.2(193 votes)

Answer

PbI_2 Explanation 1. Identify the reaction The reaction between Pb(NO_3)_2 and KI forms PbI_2 as a precipitate: Pb(NO_3)_2 + 2KI \rightarrow PbI_2(s) + 2KNO_3 2. Determine the molecular formula of the precipitate From the reaction, the yellow precipitate is PbI_2.

Explanation

1. Identify the reaction<br /> The reaction between $Pb(NO_3)_2$ and KI forms $PbI_2$ as a precipitate:<br />$$ Pb(NO_3)_2 + 2KI \rightarrow PbI_2(s) + 2KNO_3 $$<br /><br />2. Determine the molecular formula of the precipitate<br /> From the reaction, the yellow precipitate is $PbI_2$.
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