QuestionAugust 26, 2025

Is the Inverse of g(x) a function? Uso the drop-down menus to oxplain. g(x)=x^2-2 Click the arrows to choose an answer from each monu. The graph of the inverse of g(x) is the reflection of the graph of g(x) across the square .The inverse of g(x) square a function because for each input of the inverse of g(x) there is square . one unique output.

Is the Inverse of g(x) a function? Uso the drop-down menus to oxplain. g(x)=x^2-2 Click the arrows to choose an answer from each monu. The graph of the inverse of g(x) is the reflection of the graph of g(x) across the square .The inverse of g(x) square a function because for each input of the inverse of g(x) there is square . one unique output.
Is the Inverse of g(x) a function? Uso the drop-down menus to oxplain. g(x)=x^2-2 Click the arrows to choose an answer from each monu. The graph of the inverse of g(x) is the reflection of the graph of g(x) across the square .The inverse of g(x) square a function because for each input of the inverse of g(x) there is square . one unique output.

Solution
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Answer

The graph of the inverse of g(x) is the reflection of the graph of g(x) across the line y = x. The inverse of g(x) is not a function because for each input of the inverse of g(x) there is more than one unique output. Explanation 1. Identify the Reflection Line The graph of the inverse of g(x) is the reflection of the graph of g(x) across the **line y = x**. 2. Determine if the Inverse is a Function The inverse of g(x) = x^2 - 2 is not a function because for each input of the inverse of g(x) there is **more than one unique output**. This is due to the fact that g(x) is not one-to-one (it fails the horizontal line test).

Explanation

1. Identify the Reflection Line<br /> The graph of the inverse of $g(x)$ is the reflection of the graph of $g(x)$ across the **line $y = x$**.<br /><br />2. Determine if the Inverse is a Function<br /> The inverse of $g(x) = x^2 - 2$ is not a function because for each input of the inverse of $g(x)$ there is **more than one unique output**. This is due to the fact that $g(x)$ is not one-to-one (it fails the horizontal line test).
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