QuestionJuly 6, 2025

6. Provide the formula unit for each compound. a. ammonium bicarbonate b. iron (II) sulfate c. magnesium phosphate d. nickel (II) acetate

6. Provide the formula unit for each compound. a. ammonium bicarbonate b. iron (II) sulfate c. magnesium phosphate d. nickel (II) acetate
6. Provide the formula unit for each compound.
a. ammonium bicarbonate
b. iron (II) sulfate
c. magnesium phosphate
d. nickel (II) acetate

Solution
4.7(200 votes)

Answer

a. NH_4HCO_3 ### b. FeSO_4 ### c. Mg_3(PO_4)_2 ### d. Ni(CH_3COO)_2 Explanation 1. Determine the formula for ammonium bicarbonate Ammonium ion is NH_4^+ and bicarbonate ion is HCO_3^-. Combine them to form NH_4HCO_3. 2. Determine the formula for iron(II) sulfate Iron(II) ion is Fe^{2+} and sulfate ion is SO_4^{2-}. Combine them to form FeSO_4. 3. Determine the formula for magnesium phosphate Magnesium ion is Mg^{2+} and phosphate ion is PO_4^{3-}. Use three magnesium ions and two phosphate ions to balance charges, forming Mg_3(PO_4)_2. 4. Determine the formula for nickel(II) acetate Nickel(II) ion is Ni^{2+} and acetate ion is CH_3COO^-. Use two acetate ions to balance the charge, forming Ni(CH_3COO)_2.

Explanation

1. Determine the formula for ammonium bicarbonate<br /> Ammonium ion is $NH_4^+$ and bicarbonate ion is $HCO_3^-$. Combine them to form $NH_4HCO_3$.<br /><br />2. Determine the formula for iron(II) sulfate<br /> Iron(II) ion is $Fe^{2+}$ and sulfate ion is $SO_4^{2-}$. Combine them to form $FeSO_4$.<br /><br />3. Determine the formula for magnesium phosphate<br /> Magnesium ion is $Mg^{2+}$ and phosphate ion is $PO_4^{3-}$. Use three magnesium ions and two phosphate ions to balance charges, forming $Mg_3(PO_4)_2$.<br /><br />4. Determine the formula for nickel(II) acetate<br /> Nickel(II) ion is $Ni^{2+}$ and acetate ion is $CH_3COO^-$. Use two acetate ions to balance the charge, forming $Ni(CH_3COO)_2$.
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