QuestionJune 2, 2025

How many liters of water vapor is produced when 24.7 moles of gaseous ammonia is reacted in the following reaction? No correct answer 553 liters 277 liters 184 liters 1965 liters 1 po

How many liters of water vapor is produced when 24.7 moles of gaseous ammonia is reacted in the following reaction? No correct answer 553 liters 277 liters 184 liters 1965 liters 1 po
How many liters of water vapor is produced when 24.7 moles of gaseous
ammonia is reacted in the following reaction?
No correct answer
553 liters
277 liters
184 liters
1965 liters
1 po

Solution
3.9(385 votes)

Answer

829.92 liters Explanation 1. Write the Balanced Equation The balanced chemical equation is 4 \text{NH}_3 + 5 \text{O}_2 \rightarrow 4 \text{NO} + 6 \text{H}_2\text{O}. 2. Determine Moles of Water Produced From the equation, 4 moles of \text{NH}_3 produce 6 moles of \text{H}_2\text{O}. Therefore, 24.7 moles of \text{NH}_3 will produce \frac{6}{4} \times 24.7 = 37.05 moles of \text{H}_2\text{O}. 3. Convert Moles to Liters Use the ideal gas law at standard temperature and pressure (STP), where 1 mole of gas occupies 22.4 liters. Thus, 37.05 \text{ moles} \times 22.4 \text{ L/mole} = 829.92 liters.

Explanation

1. Write the Balanced Equation<br /> The balanced chemical equation is $4 \text{NH}_3 + 5 \text{O}_2 \rightarrow 4 \text{NO} + 6 \text{H}_2\text{O}$.<br />2. Determine Moles of Water Produced<br /> From the equation, 4 moles of $\text{NH}_3$ produce 6 moles of $\text{H}_2\text{O}$. Therefore, 24.7 moles of $\text{NH}_3$ will produce $\frac{6}{4} \times 24.7 = 37.05$ moles of $\text{H}_2\text{O}$.<br />3. Convert Moles to Liters<br /> Use the ideal gas law at standard temperature and pressure (STP), where 1 mole of gas occupies 22.4 liters. Thus, $37.05 \text{ moles} \times 22.4 \text{ L/mole} = 829.92$ liters.
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