QuestionJune 26, 2025

The nuclear reaction is (}_{20)^45Caarrow _(2)^4He+underline ( ) for Calcium-45 undergoing alpha decay. a (}_{17)^45Ar b (}_{10)^47Ar c (}_{18)^41Ar d (}_{15)^49Ar A B C D

The nuclear reaction is (}_{20)^45Caarrow _(2)^4He+underline ( ) for Calcium-45 undergoing alpha decay. a (}_{17)^45Ar b (}_{10)^47Ar c (}_{18)^41Ar d (}_{15)^49Ar A B C D
The nuclear reaction is (}_{20)^45Caarrow _(2)^4He+underline ( ) for Calcium-45 undergoing alpha decay. a (}_{17)^45Ar b (}_{10)^47Ar c (}_{18)^41Ar d (}_{15)^49Ar A B C D

Solution
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Answer

c {}_{18}^{41}Ar Explanation 1. Identify Alpha Decay In alpha decay, an alpha particle ({}_{2}^{4}He) is emitted. The atomic number decreases by 2 and the mass number decreases by 4. 2. Calculate New Element Subtract 2 from the atomic number of Calcium (20 - 2 = 18) and 4 from the mass number (45 - 4 = 41). 3. Determine Resulting Element The element with atomic number 18 is Argon (Ar), resulting in {}_{18}^{41}Ar.

Explanation

1. Identify Alpha Decay<br /> In alpha decay, an alpha particle (${}_{2}^{4}He$) is emitted. The atomic number decreases by 2 and the mass number decreases by 4.<br /><br />2. Calculate New Element<br /> Subtract 2 from the atomic number of Calcium (20 - 2 = 18) and 4 from the mass number (45 - 4 = 41).<br /><br />3. Determine Resulting Element<br /> The element with atomic number 18 is Argon ($Ar$), resulting in ${}_{18}^{41}Ar$.
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