QuestionJuly 23, 2025

What is the value of the normal force if the coefficient of kinetic friction is 0.22 and the kinetic frictional force is 40 newtons? A. 8.8 newtons B. 40 newtons C. 80 newtons D. 1.8times 10^2 8 x 10 newtons

What is the value of the normal force if the coefficient of kinetic friction is 0.22 and the kinetic frictional force is 40 newtons? A. 8.8 newtons B. 40 newtons C. 80 newtons D. 1.8times 10^2 8 x 10 newtons
What is the value of the normal force if the coefficient of kinetic friction is 0.22 and the kinetic frictional force is 40 newtons?
A. 8.8 newtons
B. 40 newtons
C. 80 newtons
D. 1.8times 10^2 8 x 10 newtons

Solution
4.0(216 votes)

Answer

181.82 newtons Explanation 1. Use the formula for kinetic friction The formula for kinetic friction is f_k = \mu_k \cdot N, where f_k is the kinetic frictional force, \mu_k is the coefficient of kinetic friction, and N is the normal force. 2. Solve for the normal force Rearrange the formula to find N: N = \frac{f_k}{\mu_k}. Substitute f_k = 40\, \text{N} and \mu_k = 0.22: N = \frac{40}{0.22}.

Explanation

1. Use the formula for kinetic friction<br /> The formula for kinetic friction is $f_k = \mu_k \cdot N$, where $f_k$ is the kinetic frictional force, $\mu_k$ is the coefficient of kinetic friction, and $N$ is the normal force.<br />2. Solve for the normal force<br /> Rearrange the formula to find $N$: $N = \frac{f_k}{\mu_k}$. Substitute $f_k = 40\, \text{N}$ and $\mu_k = 0.22$: $N = \frac{40}{0.22}$.
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