QuestionMay 19, 2025

1) How many milliliters of the approximately 0.16 M prepared copper(II) sulfate stock solution are needed to prepare 100.00 milliliters of a 0.016 M copper(II) sulfate solution? square mL

1) How many milliliters of the approximately 0.16 M prepared copper(II) sulfate stock solution are needed to prepare 100.00 milliliters of a 0.016 M copper(II) sulfate solution? square mL
1) How many milliliters of the approximately 0.16 M prepared copper(II) sulfate stock solution are needed to prepare 100.00 milliliters of a 0.016 M copper(II) sulfate solution? square mL

Solution
4.7(262 votes)

Answer

10.00 mL Explanation 1. Use the dilution formula The formula for dilution is **C_1V_1 = C_2V_2**, where C_1 and V_1 are the concentration and volume of the stock solution, and C_2 and V_2 are the concentration and volume of the diluted solution. 2. Substitute known values Given C_1 = 0.16 \, \text{M}, C_2 = 0.016 \, \text{M}, and V_2 = 100.00 \, \text{mL}. Substitute these into the formula: 0.16 \times V_1 = 0.016 \times 100.00. 3. Solve for V_1 Rearrange to find V_1: V_1 = \frac{0.016 \times 100.00}{0.16}. 4. Calculate V_1 V_1 = \frac{1.6}{0.16} = 10.00 \, \text{mL}.

Explanation

1. Use the dilution formula<br /> The formula for dilution is **$C_1V_1 = C_2V_2$**, where $C_1$ and $V_1$ are the concentration and volume of the stock solution, and $C_2$ and $V_2$ are the concentration and volume of the diluted solution.<br /><br />2. Substitute known values<br /> Given $C_1 = 0.16 \, \text{M}$, $C_2 = 0.016 \, \text{M}$, and $V_2 = 100.00 \, \text{mL}$. Substitute these into the formula: $0.16 \times V_1 = 0.016 \times 100.00$.<br /><br />3. Solve for $V_1$<br /> Rearrange to find $V_1$: $V_1 = \frac{0.016 \times 100.00}{0.16}$.<br /><br />4. Calculate $V_1$<br /> $V_1 = \frac{1.6}{0.16} = 10.00 \, \text{mL}$.
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