QuestionJune 24, 2025

Solid potassium chlorate, KClO_(3) decomposes into potassium chloride and oxygen gas when heated. How many moles of oxygen form when 55.8gKClO_(3) completely decompose? 83.7 mol 0.304 mol 0.455 mol 0.683 mol

Solid potassium chlorate, KClO_(3) decomposes into potassium chloride and oxygen gas when heated. How many moles of oxygen form when 55.8gKClO_(3) completely decompose? 83.7 mol 0.304 mol 0.455 mol 0.683 mol
Solid potassium chlorate, KClO_(3) decomposes
into potassium chloride and oxygen gas when
heated. How many moles of oxygen form when
55.8gKClO_(3) completely decompose?
83.7 mol
0.304 mol
0.455 mol
0.683 mol

Solution
4.0(291 votes)

Answer

0.683 mol Explanation 1. Calculate molar mass of KClO_3 Molar mass of KClO_3 = 39.1 + 35.5 + 3 \times 16 = 122.6 \, \text{g/mol} 2. Determine moles of KClO_3 Moles of KClO_3 = \frac{55.8 \, \text{g}}{122.6 \, \text{g/mol}} = 0.455 \, \text{mol} 3. Use stoichiometry to find moles of O_2 Reaction: 2 \, KClO_3 \rightarrow 2 \, KCl + 3 \, O_2. Thus, \frac{3}{2} moles of O_2 are produced per mole of KClO_3. Moles of O_2 = 0.455 \, \text{mol} \times \frac{3}{2} = 0.683 \, \text{mol}

Explanation

1. Calculate molar mass of $KClO_3$<br /> Molar mass of $KClO_3 = 39.1 + 35.5 + 3 \times 16 = 122.6 \, \text{g/mol}$<br />2. Determine moles of $KClO_3$<br /> Moles of $KClO_3 = \frac{55.8 \, \text{g}}{122.6 \, \text{g/mol}} = 0.455 \, \text{mol}$<br />3. Use stoichiometry to find moles of $O_2$<br /> Reaction: $2 \, KClO_3 \rightarrow 2 \, KCl + 3 \, O_2$. Thus, $\frac{3}{2}$ moles of $O_2$ are produced per mole of $KClO_3$.<br /> Moles of $O_2 = 0.455 \, \text{mol} \times \frac{3}{2} = 0.683 \, \text{mol}$
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