QuestionJuly 7, 2025

4) Calculate the pH of 2.6times 10^-2 M KOH. A) 12.41 B) 15.59 C) 2.06 D) 7.00 E) 1.59

4) Calculate the pH of 2.6times 10^-2 M KOH. A) 12.41 B) 15.59 C) 2.06 D) 7.00 E) 1.59
4) Calculate the pH of 2.6times 10^-2 M KOH.
A) 12.41
B) 15.59
C) 2.06
D) 7.00
E) 1.59

Solution
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Answer

12.41 Explanation 1. Calculate pOH KOH is a strong base, so it dissociates completely. The concentration of OH⁻ ions is 2.6 \times 10^{-2} M. **pOH = -\log[OH^-]**. Thus, pOH = -\log(2.6 \times 10^{-2}). 2. Calculate pH Use the relation **pH + pOH = 14**. Therefore, pH = 14 - pOH.

Explanation

1. Calculate pOH<br /> KOH is a strong base, so it dissociates completely. The concentration of OH⁻ ions is $2.6 \times 10^{-2}$ M. **pOH = -\log[OH^-]**. Thus, pOH = $-\log(2.6 \times 10^{-2})$.<br /><br />2. Calculate pH<br /> Use the relation **pH + pOH = 14**. Therefore, pH = 14 - pOH.
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