QuestionAugust 26, 2025

Find the product. (2x+3)(x+5) 3x^2+x+8 10x+15 2x^2+13x+5 2x^2+3x

Find the product. (2x+3)(x+5) 3x^2+x+8 10x+15 2x^2+13x+5 2x^2+3x
Find the product.
(2x+3)(x+5)
3x^2+x+8
10x+15
2x^2+13x+5
2x^2+3x

Solution
4.3(139 votes)

Answer

6x^4 + 41x^3 + 74x^2 + 119x + 120 Explanation 1. Expand the first expression Use distributive property: (2x+3)(x+5) = 2x(x+5) + 3(x+5). Calculate: 2x^2 + 10x + 3x + 15 = 2x^2 + 13x + 15. 2. Multiply with second expression Multiply: (2x^2 + 13x + 15)(3x^2 + x + 8). Distribute each term of the first polynomial across the second polynomial. 3. Calculate individual products 2x^2 \cdot 3x^2 = 6x^4, 2x^2 \cdot x = 2x^3, 2x^2 \cdot 8 = 16x^2. 13x \cdot 3x^2 = 39x^3, 13x \cdot x = 13x^2, 13x \cdot 8 = 104x. 15 \cdot 3x^2 = 45x^2, 15 \cdot x = 15x, 15 \cdot 8 = 120. 4. Combine like terms Sum: 6x^4 + (2x^3 + 39x^3) + (16x^2 + 13x^2 + 45x^2) + (104x + 15x) + 120. Result: 6x^4 + 41x^3 + 74x^2 + 119x + 120.

Explanation

1. Expand the first expression<br /> Use distributive property: $(2x+3)(x+5) = 2x(x+5) + 3(x+5)$.<br /> Calculate: $2x^2 + 10x + 3x + 15 = 2x^2 + 13x + 15$.<br /><br />2. Multiply with second expression<br /> Multiply: $(2x^2 + 13x + 15)(3x^2 + x + 8)$.<br /> Distribute each term of the first polynomial across the second polynomial.<br /><br />3. Calculate individual products<br /> $2x^2 \cdot 3x^2 = 6x^4$, $2x^2 \cdot x = 2x^3$, $2x^2 \cdot 8 = 16x^2$.<br /> $13x \cdot 3x^2 = 39x^3$, $13x \cdot x = 13x^2$, $13x \cdot 8 = 104x$.<br /> $15 \cdot 3x^2 = 45x^2$, $15 \cdot x = 15x$, $15 \cdot 8 = 120$.<br /><br />4. Combine like terms<br /> Sum: $6x^4 + (2x^3 + 39x^3) + (16x^2 + 13x^2 + 45x^2) + (104x + 15x) + 120$.<br /> Result: $6x^4 + 41x^3 + 74x^2 + 119x + 120$.
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