QuestionSeptember 20, 2025

Determine the equation of the slant asymptote for the equation f(x)=(x^2+3)/(x-1) Give your answer in the form ' y=mx+b' Provide your answer below: y=square

Determine the equation of the slant asymptote for the equation f(x)=(x^2+3)/(x-1) Give your answer in the form ' y=mx+b' Provide your answer below: y=square
Determine the equation of the slant asymptote
for the equation
f(x)=(x^2+3)/(x-1)
Give your answer in the form ' y=mx+b'
Provide your answer below:
y=square

Solution
4.6(221 votes)

Answer

y = x + 1 Explanation 1. Perform polynomial long division Divide x^2 + 3 by x - 1. The first term is x, since x^2 \div x = x. 2. Multiply and subtract x(x-1) = x^2 - x. Subtract: (x^2 + 3) - (x^2 - x) = x + 3. 3. Continue division x + 3 divided by x - 1 gives 1, since x \div x = 1. 4. Multiply and subtract again 1(x-1) = x - 1. Subtract: (x + 3) - (x - 1) = 4. 5. Identify slant asymptote Ignore remainder. Slant asymptote is y = x + 1.

Explanation

1. Perform polynomial long division<br /> Divide $x^2 + 3$ by $x - 1$. The first term is $x$, since $x^2 \div x = x$.<br />2. Multiply and subtract<br /> $x(x-1) = x^2 - x$. Subtract: $(x^2 + 3) - (x^2 - x) = x + 3$.<br />3. Continue division<br /> $x + 3$ divided by $x - 1$ gives $1$, since $x \div x = 1$.<br />4. Multiply and subtract again<br /> $1(x-1) = x - 1$. Subtract: $(x + 3) - (x - 1) = 4$.<br />5. Identify slant asymptote<br /> Ignore remainder. Slant asymptote is $y = x + 1$.
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