QuestionJune 2, 2025

12. How much interest will you pay during the 14^th year of a 350,000 house price, 15 year, 6.5% monthly compounded, 80 LTV loan? None of these are valid answers 2779.11 7755.94 14,627.41 13,968.37

12. How much interest will you pay during the 14^th year of a 350,000 house price, 15 year, 6.5% monthly compounded, 80 LTV loan? None of these are valid answers 2779.11 7755.94 14,627.41 13,968.37
12. How much interest will you pay during the 14^th year of a 350,000 house
price, 15 year, 6.5%  monthly compounded, 80 LTV loan?
None of these are valid answers
 2779.11
 7755.94
 14,627.41
 13,968.37

Solution
4.7(286 votes)

Answer

None of these are valid answers Explanation 1. Calculate Loan Amount Loan-to-Value (LTV) is 80%, so loan amount = 0.8 \times 350,000 = \280,000. 2. Calculate Monthly Interest Rate Annual rate is 6.5%, so monthly rate = \frac{6.5\%}{12} = 0.5417\% = 0.005417. 3. Calculate Monthly Payment Use formula for monthly payment: **M = P \frac{r(1+r)^n}{(1+r)^n - 1}**, where P = 280,000, r = 0.005417, n = 180. M = 280,000 \times \frac{0.005417(1+0.005417)^{180}}{(1+0.005417)^{180} - 1} \approx 2434.24. 4. Calculate Total Payments by Year 13 Total payments after 13 years = 2434.24 \times 12 \times 13 = 379,366.88. 5. Calculate Remaining Balance After Year 13 Use remaining balance formula: **B = P(1+r)^n - M \frac{(1+r)^n - 1}{r}** for n = 156. B = 280,000(1+0.005417)^{156} - 2434.24 \frac{(1+0.005417)^{156} - 1}{0.005417} \approx 36,876.25. 6. Calculate Interest Paid in Year 14 Interest for year 14 = B \times r \times 12 = 36,876.25 \times 0.005417 \times 12 \approx 2,394.11.

Explanation

1. Calculate Loan Amount<br /> Loan-to-Value (LTV) is 80%, so loan amount = $0.8 \times 350,000 = \$280,000$.<br /><br />2. Calculate Monthly Interest Rate<br /> Annual rate is 6.5%, so monthly rate = $\frac{6.5\%}{12} = 0.5417\% = 0.005417$.<br /><br />3. Calculate Monthly Payment<br /> Use formula for monthly payment: **$M = P \frac{r(1+r)^n}{(1+r)^n - 1}$**, where $P = 280,000$, $r = 0.005417$, $n = 180$.<br /> $M = 280,000 \times \frac{0.005417(1+0.005417)^{180}}{(1+0.005417)^{180} - 1} \approx 2434.24$.<br /><br />4. Calculate Total Payments by Year 13<br /> Total payments after 13 years = $2434.24 \times 12 \times 13 = 379,366.88$.<br /><br />5. Calculate Remaining Balance After Year 13<br /> Use remaining balance formula: **$B = P(1+r)^n - M \frac{(1+r)^n - 1}{r}$** for $n = 156$.<br /> $B = 280,000(1+0.005417)^{156} - 2434.24 \frac{(1+0.005417)^{156} - 1}{0.005417} \approx 36,876.25$.<br /><br />6. Calculate Interest Paid in Year 14<br /> Interest for year 14 = $B \times r \times 12 = 36,876.25 \times 0.005417 \times 12 \approx 2,394.11$.
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