QuestionJune 17, 2025

6.2 g of an ionic compound is dissolved in a coffee-cup calorimeter containing 100.0 g of water at 16.2^circ C The temperature of water increased to 19.5^circ C What is the Delta H of the dissolution process in kJ/mol of compound)? Assume that the specific heat of the solution is same as specific heat of water (4.184 J/g^circ C) The molar mass of the ionic compound is 72.1g/mol

6.2 g of an ionic compound is dissolved in a coffee-cup calorimeter containing 100.0 g of water at 16.2^circ C The temperature of water increased to 19.5^circ C What is the Delta H of the dissolution process in kJ/mol of compound)? Assume that the specific heat of the solution is same as specific heat of water (4.184 J/g^circ C) The molar mass of the ionic compound is 72.1g/mol
6.2 g of an ionic compound is dissolved in a coffee-cup calorimeter containing 100.0
g of water at 16.2^circ C The temperature of water increased to 19.5^circ C What is the Delta H
of the dissolution process in kJ/mol of compound)?
Assume that the specific heat of the solution is same as specific heat of water (4.184
J/g^circ C)
The molar mass of the ionic compound is 72.1g/mol

Solution
4.0(214 votes)

Answer

16.06 \, kJ/mol Explanation 1. Calculate the heat absorbed by water Use q = m \cdot c \cdot \Delta T. Here, m = 100.0 \, g, c = 4.184 \, J/g^{\circ}C, \Delta T = 19.5 - 16.2 = 3.3^{\circ}C. q = 100.0 \cdot 4.184 \cdot 3.3 = 1380.72 \, J. 2. Convert heat to kJ 1380.72 \, J = 1.38072 \, kJ. 3. Calculate moles of compound Moles = \frac{6.2 \, g}{72.1 \, g/mol} = 0.086 \, mol. 4. Calculate \Delta H in kJ/mol \Delta H = \frac{1.38072 \, kJ}{0.086 \, mol} = 16.06 \, kJ/mol.

Explanation

1. Calculate the heat absorbed by water<br /> Use $q = m \cdot c \cdot \Delta T$. Here, $m = 100.0 \, g$, $c = 4.184 \, J/g^{\circ}C$, $\Delta T = 19.5 - 16.2 = 3.3^{\circ}C$.<br /> $q = 100.0 \cdot 4.184 \cdot 3.3 = 1380.72 \, J$.<br /><br />2. Convert heat to kJ<br /> $1380.72 \, J = 1.38072 \, kJ$.<br /><br />3. Calculate moles of compound<br /> Moles = $\frac{6.2 \, g}{72.1 \, g/mol} = 0.086 \, mol$.<br /><br />4. Calculate $\Delta H$ in $kJ/mol$<br /> $\Delta H = \frac{1.38072 \, kJ}{0.086 \, mol} = 16.06 \, kJ/mol$.
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