QuestionJuly 16, 2025

The system below was at equilibrium in a 2.0 L container . What change will occur for the system when the container is shrunk to 1.0 L? 2NO(g)+O_(2)(g)leftharpoons 2NO_(2)(g)+113.06kJ Hint: How many moles of gas are on each side? The reaction shifts to the left (reactants) to produce more moles of gas. The reaction shifts to the right (products) to produce fewer moles of gas. There is no change because there are the same number of moles of gas on both sides.

The system below was at equilibrium in a 2.0 L container . What change will occur for the system when the container is shrunk to 1.0 L? 2NO(g)+O_(2)(g)leftharpoons 2NO_(2)(g)+113.06kJ Hint: How many moles of gas are on each side? The reaction shifts to the left (reactants) to produce more moles of gas. The reaction shifts to the right (products) to produce fewer moles of gas. There is no change because there are the same number of moles of gas on both sides.
The system below was at equilibrium in a 2.0 L container . What change will occur for the system when the container is shrunk to 1.0 L? 2NO(g)+O_(2)(g)leftharpoons 2NO_(2)(g)+113.06kJ Hint: How many moles of gas are on each side? The reaction shifts to the left (reactants) to produce more moles of gas. The reaction shifts to the right (products) to produce fewer moles of gas. There is no change because there are the same number of moles of gas on both sides.

Solution
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Answer

The reaction shifts to the right (products) to produce fewer moles of gas. Explanation 1. Count Moles of Gas on Each Side On the left, there are 3 moles of gas (2NO + O_2). On the right, there are 2 moles of gas (2NO_2). 2. Apply Le Chatelier's Principle Reducing volume increases pressure. The system shifts to the side with fewer moles of gas to reduce pressure.

Explanation

1. Count Moles of Gas on Each Side<br /> On the left, there are 3 moles of gas ($2NO + O_2$). On the right, there are 2 moles of gas ($2NO_2$).<br /><br />2. Apply Le Chatelier's Principle<br /> Reducing volume increases pressure. The system shifts to the side with fewer moles of gas to reduce pressure.
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