QuestionJune 30, 2025

A circular coil of radius 20 cm (you need to find the area of the coil)is oriented such that it makes an angle of 60 degrees with the electric field. of strength 2000N/C What electric flux in N.m^2/C passes through the coil?[Area of a circle A=pi r^2 218 92 (C) C 126 113

A circular coil of radius 20 cm (you need to find the area of the coil)is oriented such that it makes an angle of 60 degrees with the electric field. of strength 2000N/C What electric flux in N.m^2/C passes through the coil?[Area of a circle A=pi r^2 218 92 (C) C 126 113
A circular coil of radius 20 cm (you need to find the area of the coil)is oriented such that it makes an angle of 60 degrees with the electric field. of strength 2000N/C What electric flux in N.m^2/C passes through the coil?[Area of a circle A=pi r^2 218 92 (C) C 126 113

Solution
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Answer

40\pi \, \text{N}\cdot\text{m}^2/\text{C} Explanation 1. Calculate the Area of the Coil The radius r is 20 cm, which is 0.2 m. Use the formula for the area of a circle: **A = \pi r^2**. Thus, A = \pi (0.2)^2 = 0.04\pi \, \text{m}^2. 2. Calculate the Electric Flux The electric flux \Phi is given by **\Phi = E \cdot A \cdot \cos(\theta)**, where E = 2000 \, \text{N/C} and \theta = 60^\circ. Therefore, \Phi = 2000 \times 0.04\pi \times \cos(60^\circ). Since \cos(60^\circ) = 0.5, \Phi = 2000 \times 0.04\pi \times 0.5 = 40\pi \, \text{N}\cdot\text{m}^2/\text{C}.

Explanation

1. Calculate the Area of the Coil<br /> The radius $r$ is 20 cm, which is 0.2 m. Use the formula for the area of a circle: **$A = \pi r^2$**. Thus, $A = \pi (0.2)^2 = 0.04\pi \, \text{m}^2$.<br /><br />2. Calculate the Electric Flux<br /> The electric flux $\Phi$ is given by **$\Phi = E \cdot A \cdot \cos(\theta)$**, where $E = 2000 \, \text{N/C}$ and $\theta = 60^\circ$. Therefore, $\Phi = 2000 \times 0.04\pi \times \cos(60^\circ)$. Since $\cos(60^\circ) = 0.5$, $\Phi = 2000 \times 0.04\pi \times 0.5 = 40\pi \, \text{N}\cdot\text{m}^2/\text{C}$.
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