QuestionJuly 15, 2025

Calculate the number of moles in 100.0 g of each of the following compounds. Be sure each of your answer entries has the correct number of significant figures. Part 1 of 3 MgSO_(4) square mol MgSO_(4) Part 2 of 3 NaAl(SO_(4))_(2) square molNaAl(SO_(4))_(2) Part 3 of 3 NH_(3) mol NH_(3)

Calculate the number of moles in 100.0 g of each of the following compounds. Be sure each of your answer entries has the correct number of significant figures. Part 1 of 3 MgSO_(4) square mol MgSO_(4) Part 2 of 3 NaAl(SO_(4))_(2) square molNaAl(SO_(4))_(2) Part 3 of 3 NH_(3) mol NH_(3)
Calculate the number of moles in 100.0 g of each of the following compounds. Be sure each of your answer entries has the correct number of significant figures.
Part 1 of 3
MgSO_(4)
square  mol MgSO_(4)
Part 2 of 3
NaAl(SO_(4))_(2)
square molNaAl(SO_(4))_(2)
Part 3 of 3
NH_(3)
mol NH_(3)

Solution
4.6(215 votes)

Answer

0.831 mol MgSO_{4} ### 0.292 mol NaAl(SO_{4})_{2} ### 5.87 mol NH_{3} Explanation 1. Calculate Molar Mass of MgSO_{4} Molar mass = 24.31 (Mg) + 32.07 (S) + 4 × 16.00 (O) = 120.37 g/mol 2. Calculate Moles of MgSO_{4} **Moles = \frac{\text{mass}}{\text{molar mass}}** = \frac{100.0 \, \text{g}}{120.37 \, \text{g/mol}} 3. Calculate Molar Mass of NaAl(SO_{4})_{2} Molar mass = 22.99 (Na) + 26.98 (Al) + 2 × [32.07 (S) + 4 × 16.00 (O)] = 342.15 g/mol 4. Calculate Moles of NaAl(SO_{4})_{2} **Moles = \frac{\text{mass}}{\text{molar mass}}** = \frac{100.0 \, \text{g}}{342.15 \, \text{g/mol}} 5. Calculate Molar Mass of NH_{3} Molar mass = 14.01 (N) + 3 × 1.01 (H) = 17.04 g/mol 6. Calculate Moles of NH_{3} **Moles = \frac{\text{mass}}{\text{molar mass}}** = \frac{100.0 \, \text{g}}{17.04 \, \text{g/mol}}

Explanation

1. Calculate Molar Mass of $MgSO_{4}$<br /> Molar mass = 24.31 (Mg) + 32.07 (S) + 4 × 16.00 (O) = 120.37 g/mol<br /><br />2. Calculate Moles of $MgSO_{4}$<br /> **Moles = \frac{\text{mass}}{\text{molar mass}}** = $\frac{100.0 \, \text{g}}{120.37 \, \text{g/mol}}$<br /><br />3. Calculate Molar Mass of $NaAl(SO_{4})_{2}$<br /> Molar mass = 22.99 (Na) + 26.98 (Al) + 2 × [32.07 (S) + 4 × 16.00 (O)] = 342.15 g/mol<br /><br />4. Calculate Moles of $NaAl(SO_{4})_{2}$<br /> **Moles = \frac{\text{mass}}{\text{molar mass}}** = $\frac{100.0 \, \text{g}}{342.15 \, \text{g/mol}}$<br /><br />5. Calculate Molar Mass of $NH_{3}$<br /> Molar mass = 14.01 (N) + 3 × 1.01 (H) = 17.04 g/mol<br /><br />6. Calculate Moles of $NH_{3}$<br /> **Moles = \frac{\text{mass}}{\text{molar mass}}** = $\frac{100.0 \, \text{g}}{17.04 \, \text{g/mol}}$
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