QuestionJuly 23, 2025

Based on molecular orbital theory, the bond order of the H-H bond in the H_(2)^+ ion is __ 1/2 3/2 2 1

Based on molecular orbital theory, the bond order of the H-H bond in the H_(2)^+ ion is __ 1/2 3/2 2 1
Based on molecular orbital theory, the bond order of the H-H bond in the H_(2)^+ ion is __ 1/2 3/2 2 1

Solution
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Answer

\frac{1}{2} Explanation 1. Identify Molecular Orbitals H_2^+ has one electron. It occupies the bonding molecular orbital (\sigma_{1s}). 2. Calculate Bond Order **Bond order** is calculated as \frac{\text{(Number of electrons in bonding orbitals)} - \text{(Number of electrons in antibonding orbitals)}}{2}. For H_2^+, there is 1 electron in a bonding orbital and 0 in an antibonding orbital. 3. Apply Formula Bond order = \frac{1 - 0}{2} = \frac{1}{2}.

Explanation

1. Identify Molecular Orbitals<br /> $H_2^+$ has one electron. It occupies the bonding molecular orbital ($\sigma_{1s}$).<br /><br />2. Calculate Bond Order<br /> **Bond order** is calculated as $\frac{\text{(Number of electrons in bonding orbitals)} - \text{(Number of electrons in antibonding orbitals)}}{2}$. For $H_2^+$, there is 1 electron in a bonding orbital and 0 in an antibonding orbital.<br /><br />3. Apply Formula<br /> Bond order = $\frac{1 - 0}{2} = \frac{1}{2}$.
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