QuestionAugust 27, 2025

According to the fundamental theorem of algebra, how many zeros does the polynomial below have? f(x)=x^3-10x^2+27x-12

According to the fundamental theorem of algebra, how many zeros does the polynomial below have? f(x)=x^3-10x^2+27x-12
According to the fundamental theorem of algebra, how many zeros does the
polynomial below have?
f(x)=x^3-10x^2+27x-12

Solution
4.7(163 votes)

Answer

3 Explanation 1. Identify the Degree of the Polynomial The polynomial f(x) = x^3 - 10x^2 + 27x - 12 is a cubic polynomial. 2. Apply the Fundamental Theorem of Algebra The fundamental theorem of algebra states that a polynomial of degree n has exactly n zeros (including multiplicities and complex zeros).

Explanation

1. Identify the Degree of the Polynomial<br /> The polynomial $f(x) = x^3 - 10x^2 + 27x - 12$ is a cubic polynomial.<br />2. Apply the Fundamental Theorem of Algebra<br /> The fundamental theorem of algebra states that a polynomial of degree $n$ has exactly $n$ zeros (including multiplicities and complex zeros).
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