QuestionAugust 5, 2025

Question 17 of 30 What is the predicted change in the boiling point of water when 2.10 g of barium chloride (BaCl_(2)) is dissolved in 5 .50 kg of water? K_(b)of water=0.51^circ C/mol molar mass BaCl_(2)=208.23g/mol i value of BaCl_(2)=3 A. -0.00031^circ C B. 0.0028^circ C C. 0.00093^circ C D. -0.194^circ C

Question 17 of 30 What is the predicted change in the boiling point of water when 2.10 g of barium chloride (BaCl_(2)) is dissolved in 5 .50 kg of water? K_(b)of water=0.51^circ C/mol molar mass BaCl_(2)=208.23g/mol i value of BaCl_(2)=3 A. -0.00031^circ C B. 0.0028^circ C C. 0.00093^circ C D. -0.194^circ C
Question 17 of 30 What is the predicted change in the boiling point of water when 2.10 g of barium chloride (BaCl_(2)) is dissolved in 5 .50 kg of water? K_(b)of water=0.51^circ C/mol molar mass BaCl_(2)=208.23g/mol i value of BaCl_(2)=3 A. -0.00031^circ C B. 0.0028^circ C C. 0.00093^circ C D. -0.194^circ C

Solution
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Answer

B. 0.0028^{\circ }C Explanation 1. Calculate moles of BaCl_2 Moles = \frac{\text{mass}}{\text{molar mass}} = \frac{2.10 \, \text{g}}{208.23 \, \text{g/mol}} = 0.01008 \, \text{mol} 2. Calculate molality Molality (m) = \frac{\text{moles of solute}}{\text{kg of solvent}} = \frac{0.01008 \, \text{mol}}{5.50 \, \text{kg}} = 0.00183 \, \text{mol/kg} 3. Calculate boiling point elevation Boiling point elevation (\Delta T_b) = i \cdot K_b \cdot m = 3 \cdot 0.51 \, ^\circ C/\text{mol} \cdot 0.00183 \, \text{mol/kg} = 0.0028 \, ^\circ C

Explanation

1. Calculate moles of $BaCl_2$<br /> Moles = $\frac{\text{mass}}{\text{molar mass}} = \frac{2.10 \, \text{g}}{208.23 \, \text{g/mol}} = 0.01008 \, \text{mol}$<br />2. Calculate molality<br /> Molality ($m$) = $\frac{\text{moles of solute}}{\text{kg of solvent}} = \frac{0.01008 \, \text{mol}}{5.50 \, \text{kg}} = 0.00183 \, \text{mol/kg}$<br />3. Calculate boiling point elevation<br /> Boiling point elevation ($\Delta T_b$) = $i \cdot K_b \cdot m = 3 \cdot 0.51 \, ^\circ C/\text{mol} \cdot 0.00183 \, \text{mol/kg} = 0.0028 \, ^\circ C$
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