QuestionJune 17, 2025

Identify the properly written and balanced equation for the precipitation reaction between ammonium sulfide and cobalt(II) chloride. (NH_(4))_(2)S+2CoCl_(2)arrow CoS+NH_(4)Cl NH_(4)S+CoCl_(2)arrow 2CoS_(2)+2NH_(4)Cl (NH_(4))_(2)S+CoCl_(2)arrow CoS+2NH_(4)Cl NH_(4)S+CoClarrow CoS+NH_(4)Cl

Identify the properly written and balanced equation for the precipitation reaction between ammonium sulfide and cobalt(II) chloride. (NH_(4))_(2)S+2CoCl_(2)arrow CoS+NH_(4)Cl NH_(4)S+CoCl_(2)arrow 2CoS_(2)+2NH_(4)Cl (NH_(4))_(2)S+CoCl_(2)arrow CoS+2NH_(4)Cl NH_(4)S+CoClarrow CoS+NH_(4)Cl
Identify the properly written and balanced equation for the precipitation reaction between ammonium
sulfide and cobalt(II) chloride.
(NH_(4))_(2)S+2CoCl_(2)arrow CoS+NH_(4)Cl
NH_(4)S+CoCl_(2)arrow 2CoS_(2)+2NH_(4)Cl
(NH_(4))_(2)S+CoCl_(2)arrow CoS+2NH_(4)Cl
NH_(4)S+CoClarrow CoS+NH_(4)Cl

Solution
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Answer

(NH_{4})_{2}S + CoCl_{2} \rightarrow CoS + 2NH_{4}Cl Explanation 1. Identify reactants and products Ammonium sulfide is (NH_{4})_{2}S and cobalt(II) chloride is CoCl_{2}. The precipitation product is cobalt(II) sulfide, CoS, and the byproduct is ammonium chloride, NH_{4}Cl. 2. Balance the equation Ensure the number of each type of atom is equal on both sides. For (NH_{4})_{2}S + CoCl_{2} \rightarrow CoS + 2NH_{4}Cl, balance as follows: - 1 Co on both sides. - 1 S on both sides. - 2 NH_4^+ ions on both sides. - 2 Cl^- ions on both sides.

Explanation

1. Identify reactants and products<br /> Ammonium sulfide is $(NH_{4})_{2}S$ and cobalt(II) chloride is $CoCl_{2}$. The precipitation product is cobalt(II) sulfide, $CoS$, and the byproduct is ammonium chloride, $NH_{4}Cl$.<br />2. Balance the equation<br /> Ensure the number of each type of atom is equal on both sides. For $(NH_{4})_{2}S + CoCl_{2} \rightarrow CoS + 2NH_{4}Cl$, balance as follows:<br />- 1 $Co$ on both sides.<br />- 1 $S$ on both sides.<br />- 2 $NH_4^+$ ions on both sides.<br />- 2 $Cl^-$ ions on both sides.
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