QuestionMay 9, 2025

What is the bond order of F_(2) Express your answer numerically as an integer. View Available Hint(s) square

What is the bond order of F_(2) Express your answer numerically as an integer. View Available Hint(s) square
What is the bond order of F_(2) Express your answer numerically as an integer. View Available Hint(s) square

Solution
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Answer

2 Explanation 1. Determine the total number of electrons in F_2 Fluorine has 9 electrons, so F_2 has 2 \times 9 = 18 electrons. 2. Fill molecular orbitals Use molecular orbital theory. The electron configuration for F_2 is: \sigma(2s)^2, \sigma^*(2s)^2, \sigma(2p_z)^2, \pi(2p_x)^2, \pi(2p_y)^2, \pi^*(2p_x)^2, \pi^*(2p_y)^2. 3. Apply bond order formula Bond order = \frac{\text{Number of bonding electrons} - \text{Number of antibonding electrons}}{2}. Bonding electrons = 2 + 2 + 2 + 2 = 8, Antibonding electrons = 2 + 2 = 4. Bond order = \frac{8 - 4}{2} = 2.

Explanation

1. Determine the total number of electrons in $F_2$<br /> Fluorine has 9 electrons, so $F_2$ has $2 \times 9 = 18$ electrons.<br /><br />2. Fill molecular orbitals<br /> Use molecular orbital theory. The electron configuration for $F_2$ is:<br />$\sigma(2s)^2, \sigma^*(2s)^2, \sigma(2p_z)^2, \pi(2p_x)^2, \pi(2p_y)^2, \pi^*(2p_x)^2, \pi^*(2p_y)^2$.<br /><br />3. Apply bond order formula<br /> Bond order = $\frac{\text{Number of bonding electrons} - \text{Number of antibonding electrons}}{2}$.<br />Bonding electrons = $2 + 2 + 2 + 2 = 8$, Antibonding electrons = $2 + 2 = 4$. <br />Bond order = $\frac{8 - 4}{2} = 2$.
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