QuestionJuly 10, 2025

The heat of vaporization for water is 540cal/g How many kilocalories are needed to change 7 g of liquid water to steam at 100^circ C ? Treat the heat of vaporization as exact. square

The heat of vaporization for water is 540cal/g How many kilocalories are needed to change 7 g of liquid water to steam at 100^circ C ? Treat the heat of vaporization as exact. square
The heat of vaporization for water is 540cal/g How many kilocalories
are needed to change 7 g of liquid water to steam at 100^circ C ? Treat the
heat of vaporization as exact.
square

Solution
4.7(236 votes)

Answer

3.78 kcal Explanation 1. Convert grams to kilocalories Multiply the mass of water by the heat of vaporization and convert calories to kilocalories. Use the formula: \text{Energy (kcal)} = \frac{\text{mass (g)} \times \text{heat of vaporization (cal/g)}}{1000} . 2. Calculate the energy \text{Energy (kcal)} = \frac{7 \, \text{g} \times 540 \, \text{cal/g}}{1000} = 3.78 \, \text{kcal} .

Explanation

1. Convert grams to kilocalories<br /> Multiply the mass of water by the heat of vaporization and convert calories to kilocalories. Use the formula: $ \text{Energy (kcal)} = \frac{\text{mass (g)} \times \text{heat of vaporization (cal/g)}}{1000} $.<br />2. Calculate the energy<br /> $ \text{Energy (kcal)} = \frac{7 \, \text{g} \times 540 \, \text{cal/g}}{1000} = 3.78 \, \text{kcal} $.
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