QuestionJuly 13, 2025

What is the missing product of the following Fusion reaction? 2_(6)^12Carrow _(2)^4He+ __ (}_{10)^20Ne (}_{11)^21Na (}_{11)^20Na (}_{10)^21Ne

What is the missing product of the following Fusion reaction? 2_(6)^12Carrow _(2)^4He+ __ (}_{10)^20Ne (}_{11)^21Na (}_{11)^20Na (}_{10)^21Ne
What is the missing product of the following Fusion reaction? 2_(6)^12Carrow _(2)^4He+ __ (}_{10)^20Ne (}_{11)^21Na (}_{11)^20Na (}_{10)^21Ne

Solution
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Answer

_{4}^{8}Be Explanation 1. Identify the reaction type This is a fusion reaction where ^{12}_{6}C splits into _{2}^{4}He and another product. 2. Apply conservation of atomic number The atomic number must be conserved. Carbon has an atomic number of 6, and Helium has an atomic number of 2. Therefore, the missing product must have an atomic number of 6 - 2 = 4. 3. Apply conservation of mass number The mass number must also be conserved. Carbon has a mass number of 12, and Helium has a mass number of 4. Therefore, the missing product must have a mass number of 12 - 4 = 8. 4. Determine the missing product The element with atomic number 4 is Beryllium (Be), so the missing product is _{4}^{8}Be.

Explanation

1. Identify the reaction type<br /> This is a fusion reaction where $^{12}_{6}C$ splits into $_{2}^{4}He$ and another product.<br />2. Apply conservation of atomic number<br /> The atomic number must be conserved. Carbon has an atomic number of 6, and Helium has an atomic number of 2. Therefore, the missing product must have an atomic number of $6 - 2 = 4$.<br />3. Apply conservation of mass number<br /> The mass number must also be conserved. Carbon has a mass number of 12, and Helium has a mass number of 4. Therefore, the missing product must have a mass number of $12 - 4 = 8$.<br />4. Determine the missing product<br /> The element with atomic number 4 is Beryllium ($Be$), so the missing product is $_{4}^{8}Be$.
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