QuestionApril 19, 2025

Fill in the left side of this equilibrium constant equation for the reaction of nitrous acid (HNO_(2)) with water. square =K_(a)

Fill in the left side of this equilibrium constant equation for the reaction of nitrous acid (HNO_(2)) with water. square =K_(a)
Fill in the left side of this equilibrium constant equation for the reaction of nitrous acid (HNO_(2)) with water.
square =K_(a)

Solution
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Answer

\frac NO_2^-][H_3O^+ HNO_2 = K_{a} Explanation 1. Write the chemical equation The reaction of nitrous acid with water is HNO_2 + H_2O \rightleftharpoons NO_2^- + H_3O^+. 2. Write the expression for the equilibrium constant For the dissociation of an acid in water, the equilibrium constant (K_a) is given by **K_a = \frac NO_2^-][H_3O^+ HNO_2 **.

Explanation

1. Write the chemical equation<br /> The reaction of nitrous acid with water is $HNO_2 + H_2O \rightleftharpoons NO_2^- + H_3O^+$.<br /><br />2. Write the expression for the equilibrium constant<br /> For the dissociation of an acid in water, the equilibrium constant ($K_a$) is given by **$K_a = \frac{[NO_2^-][H_3O^+]}{[HNO_2]}$**.
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