QuestionJune 4, 2025

1) How many milliliters of the approximately 0.16 M prepared copper (H) sulfate stock solution are needed to prepare 100 .00 milliliters of a 0 ,016 M copper(II) sulfate solution? square mL

1) How many milliliters of the approximately 0.16 M prepared copper (H) sulfate stock solution are needed to prepare 100 .00 milliliters of a 0 ,016 M copper(II) sulfate solution? square mL
1) How many milliliters of the approximately 0.16 M prepared copper (H) sulfate stock solution are needed to prepare 100 .00 milliliters of a 0 ,016 M
copper(II) sulfate solution?
square  mL

Solution
4.1(255 votes)

Answer

10.00 mL Explanation 1. Use the dilution formula The formula for dilution is **\( C_1V_1 = C_2V_2 \)**, where \( C_1 \) and \( V_1 \) are the concentration and volume of the stock solution, and \( C_2 \) and \( V_2 \) are the concentration and volume of the diluted solution. 2. Substitute known values Given \( C_1 = 0.16 \, \text{M} \), \( C_2 = 0.016 \, \text{M} \), and \( V_2 = 100.00 \, \text{mL} \). Substitute these into the formula: \[ 0.16 \times V_1 = 0.016 \times 100.00 \] 3. Solve for \( V_1 \) Rearrange to find \( V_1 \): \[ V_1 = \frac{0.016 \times 100.00}{0.16} \] 4. Calculate \( V_1 \) Perform the calculation: \[ V_1 = \frac{1.6}{0.16} = 10.00 \, \text{mL} \]

Explanation

1. Use the dilution formula<br /> The formula for dilution is **\( C_1V_1 = C_2V_2 \)**, where \( C_1 \) and \( V_1 \) are the concentration and volume of the stock solution, and \( C_2 \) and \( V_2 \) are the concentration and volume of the diluted solution.<br /><br />2. Substitute known values<br /> Given \( C_1 = 0.16 \, \text{M} \), \( C_2 = 0.016 \, \text{M} \), and \( V_2 = 100.00 \, \text{mL} \). Substitute these into the formula: <br />\[ 0.16 \times V_1 = 0.016 \times 100.00 \]<br /><br />3. Solve for \( V_1 \)<br /> Rearrange to find \( V_1 \):<br />\[ V_1 = \frac{0.016 \times 100.00}{0.16} \]<br /><br />4. Calculate \( V_1 \)<br /> Perform the calculation:<br />\[ V_1 = \frac{1.6}{0.16} = 10.00 \, \text{mL} \]
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