QuestionMay 3, 2025

V=11V R1=4 R2=6 R3=3Omega How many volts will the multimeter in this circuit read? Round calculation to the nearest tenth of a volt. square V

V=11V R1=4 R2=6 R3=3Omega How many volts will the multimeter in this circuit read? Round calculation to the nearest tenth of a volt. square V
V=11V R1=4 R2=6 R3=3Omega How many volts will the multimeter in this circuit read? Round calculation to the nearest tenth of a volt. square V

Solution
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Answer

14.3 V Explanation 1. Calculate Total Resistance The resistors R1 and R2 are in series, so R_{12} = R1 + R2 = 4\Omega + 6\Omega = 10\Omega. Then, R_{12} is in parallel with R3, so use **\frac{1}{R_{\text{total}}} = \frac{1}{R_{12}} + \frac{1}{R3}**. Thus, \frac{1}{R_{\text{total}}} = \frac{1}{10} + \frac{1}{3} = \frac{13}{30}, giving R_{\text{total}} = \frac{30}{13} \approx 2.31\Omega. 2. Calculate Current Using Ohm's Law Use **I = \frac{V}{R_{\text{total}}}**. So, I = \frac{11}{2.31} \approx 4.76A. 3. Calculate Voltage Across R3 Use **V = I \times R3**. So, V = 4.76 \times 3 \approx 14.28V.

Explanation

1. Calculate Total Resistance<br /> The resistors $R1$ and $R2$ are in series, so $R_{12} = R1 + R2 = 4\Omega + 6\Omega = 10\Omega$. Then, $R_{12}$ is in parallel with $R3$, so use **$\frac{1}{R_{\text{total}}} = \frac{1}{R_{12}} + \frac{1}{R3}$**. Thus, $\frac{1}{R_{\text{total}}} = \frac{1}{10} + \frac{1}{3} = \frac{13}{30}$, giving $R_{\text{total}} = \frac{30}{13} \approx 2.31\Omega$.<br />2. Calculate Current Using Ohm's Law<br /> Use **$I = \frac{V}{R_{\text{total}}}$**. So, $I = \frac{11}{2.31} \approx 4.76A$.<br />3. Calculate Voltage Across $R3$<br /> Use **$V = I \times R3$**. So, $V = 4.76 \times 3 \approx 14.28V$.
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