QuestionMay 19, 2025

The "bends" is a condition which some deep sea divers can acquire if they come up too fast from deep underwater. This is because the nitrogen N_(2) gas in their forming larger bubbles obstructing blood circulation. If a diver has 0.10 liters (L) of gas in his blood at an initial pressure of 100 atm, but then rises very quickly to blood has a new pressure of 50.0 atm of pressure, what will the new volume of gas in the blood be? 50L 201 0.20 L 0.0051

The "bends" is a condition which some deep sea divers can acquire if they come up too fast from deep underwater. This is because the nitrogen N_(2) gas in their forming larger bubbles obstructing blood circulation. If a diver has 0.10 liters (L) of gas in his blood at an initial pressure of 100 atm, but then rises very quickly to blood has a new pressure of 50.0 atm of pressure, what will the new volume of gas in the blood be? 50L 201 0.20 L 0.0051
The "bends" is a condition which some deep sea divers can acquire if they come up too fast from deep underwater. This is because the nitrogen N_(2) gas in their forming larger bubbles obstructing blood circulation. If a diver has 0.10 liters (L) of gas in his blood at an initial pressure of 100 atm, but then rises very quickly to blood has a new pressure of 50.0 atm of pressure, what will the new volume of gas in the blood be? 50L 201 0.20 L 0.0051

Solution
4.3(275 votes)

Answer

0.20 L Explanation 1. Identify the applicable gas law Use **Boyle's Law**: P_1V_1 = P_2V_2, where P is pressure and V is volume. 2. Substitute known values Given: P_1 = 100 \, \text{atm}, V_1 = 0.10 \, \text{L}, P_2 = 50.0 \, \text{atm}. Find V_2. 3. Solve for the new volume V_2 Rearrange to find V_2: V_2 = \frac{P_1V_1}{P_2} = \frac{100 \times 0.10}{50.0}. 4. Calculate the result V_2 = \frac{10}{50} = 0.20 \, \text{L}.

Explanation

1. Identify the applicable gas law<br /> Use **Boyle's Law**: $P_1V_1 = P_2V_2$, where $P$ is pressure and $V$ is volume.<br /><br />2. Substitute known values<br /> Given: $P_1 = 100 \, \text{atm}$, $V_1 = 0.10 \, \text{L}$, $P_2 = 50.0 \, \text{atm}$. Find $V_2$.<br /><br />3. Solve for the new volume $V_2$<br /> Rearrange to find $V_2$: $V_2 = \frac{P_1V_1}{P_2} = \frac{100 \times 0.10}{50.0}$.<br /><br />4. Calculate the result<br /> $V_2 = \frac{10}{50} = 0.20 \, \text{L}$.
Click to rate:

Similar Questions