QuestionJuly 19, 2025

A chemist dissolves 331 mg of pure hydrobromic acid in enough water to make up 270.mL of solution. Calculate the pH of the solution. Be sure your answer has the correct number of significant digits. square

A chemist dissolves 331 mg of pure hydrobromic acid in enough water to make up 270.mL of solution. Calculate the pH of the solution. Be sure your answer has the correct number of significant digits. square
A chemist dissolves 331 mg of pure hydrobromic acid in enough water to make up 270.mL of solution. Calculate the pH of the solution. Be sure your
answer has the correct number of significant digits.
square

Solution
4.4(237 votes)

Answer

1.00 Explanation 1. Calculate Molarity of HBr Convert mass to grams: 331 \, \text{mg} = 0.331 \, \text{g}. Molar mass of HBr is approximately 80.91 \, \text{g/mol}. Moles of HBr = \frac{0.331}{80.91}. Molarity (M) = \frac{\text{moles}}{\text{volume in L}} = \frac{0.331/80.91}{0.270}. 2. Determine [H⁺] Concentration HBr is a strong acid, so it dissociates completely: [H⁺] = Molarity of HBr. 3. Calculate pH **pH = -\log[\text{H}^+]**.

Explanation

1. Calculate Molarity of HBr<br /> Convert mass to grams: $331 \, \text{mg} = 0.331 \, \text{g}$. Molar mass of HBr is approximately $80.91 \, \text{g/mol}$. Moles of HBr = $\frac{0.331}{80.91}$. Molarity (M) = $\frac{\text{moles}}{\text{volume in L}} = \frac{0.331/80.91}{0.270}$.<br /><br />2. Determine [H⁺] Concentration<br /> HBr is a strong acid, so it dissociates completely: [H⁺] = Molarity of HBr.<br /><br />3. Calculate pH<br /> **pH = -\log[\text{H}^+]**.
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