QuestionJuly 18, 2025

The pHofa fruit juice is 5.6.Find the hydronium ion concentration, [H_(3)O^+] of the juice. Uso the formula pH=-log[H_(3)O^+] The hydronium ion concentration [H_(3)O^+] is approximately square moles per liter. (Use scientific notation. Use the multiplication symbol in the math palette as needed. Round to the nearest tenth as needed.)

The pHofa fruit juice is 5.6.Find the hydronium ion concentration, [H_(3)O^+] of the juice. Uso the formula pH=-log[H_(3)O^+] The hydronium ion concentration [H_(3)O^+] is approximately square moles per liter. (Use scientific notation. Use the multiplication symbol in the math palette as needed. Round to the nearest tenth as needed.)
The pHofa fruit juice is 5.6.Find the hydronium ion concentration, [H_(3)O^+] of the juice. Uso the formula pH=-log[H_(3)O^+]
The hydronium ion concentration [H_(3)O^+] is approximately square  moles per liter.
(Use scientific notation. Use the multiplication symbol in the math palette as needed. Round to the nearest tenth as needed.)

Solution
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Answer

1.6 \times 10^{-6} moles per liter. Explanation 1. Use the pH formula The formula is pH = -\log[H_{3}O^{+}]. Rearrange to find [H_{3}O^{+}]: [H_{3}O^{+}] = 10^{-pH}. 2. Calculate hydronium ion concentration Substitute pH = 5.8 into the formula: [H_{3}O^{+}] = 10^{-5.8}. 3. Compute the value Calculate 10^{-5.8} using a calculator to get approximately 1.6 \times 10^{-6}.

Explanation

1. Use the pH formula<br /> The formula is $pH = -\log[H_{3}O^{+}]$. Rearrange to find $[H_{3}O^{+}]$: $[H_{3}O^{+}] = 10^{-pH}$.<br /><br />2. Calculate hydronium ion concentration<br /> Substitute $pH = 5.8$ into the formula: $[H_{3}O^{+}] = 10^{-5.8}$.<br /><br />3. Compute the value<br /> Calculate $10^{-5.8}$ using a calculator to get approximately $1.6 \times 10^{-6}$.
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