QuestionMay 14, 2025

If 65.5 mL of HCl stock solution is used to make 450 mL of a.675 M HCl solution, what is the Molarity of the stock solution? (Put your answer in 3 sig.fig.) Dilution square

If 65.5 mL of HCl stock solution is used to make 450 mL of a.675 M HCl solution, what is the Molarity of the stock solution? (Put your answer in 3 sig.fig.) Dilution square
If 65.5 mL of HCl stock solution is used to make 450 mL of a.675 M HCl solution, what is the Molarity of the stock solution? (Put your answer in 3 sig.fig.) Dilution square

Solution
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Answer

4.64 M Explanation 1. Use the dilution formula The formula for dilution is M_1V_1 = M_2V_2, where M_1 and V_1 are the molarity and volume of the stock solution, and M_2 and V_2 are the molarity and volume of the diluted solution. 2. Substitute known values Given V_1 = 65.5 \text{ mL}, V_2 = 450 \text{ mL}, and M_2 = 0.675 \text{ M}, substitute these into the formula: M_1 \times 65.5 = 0.675 \times 450. 3. Solve for M_1 Rearrange to find M_1: M_1 = \frac{0.675 \times 450}{65.5}. 4. Calculate M_1 Perform the calculation: M_1 = \frac{303.75}{65.5} \approx 4.64 \text{ M}.

Explanation

1. Use the dilution formula<br /> The formula for dilution is $M_1V_1 = M_2V_2$, where $M_1$ and $V_1$ are the molarity and volume of the stock solution, and $M_2$ and $V_2$ are the molarity and volume of the diluted solution.<br /><br />2. Substitute known values<br /> Given $V_1 = 65.5 \text{ mL}$, $V_2 = 450 \text{ mL}$, and $M_2 = 0.675 \text{ M}$, substitute these into the formula: $M_1 \times 65.5 = 0.675 \times 450$.<br /><br />3. Solve for $M_1$<br /> Rearrange to find $M_1$: $M_1 = \frac{0.675 \times 450}{65.5}$.<br /><br />4. Calculate $M_1$<br /> Perform the calculation: $M_1 = \frac{303.75}{65.5} \approx 4.64 \text{ M}$.
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