QuestionFebruary 20, 2026

Write the net ionic equation between Cr_(2)(SO_(4))_(3)(aq) and Ba(OH)_(2)(aq) Be sure to include the states of matter. square

Write the net ionic equation between Cr_(2)(SO_(4))_(3)(aq) and Ba(OH)_(2)(aq) Be sure to include the states of matter. square
Write the net ionic equation between Cr_(2)(SO_(4))_(3)(aq) and Ba(OH)_(2)(aq) Be sure to include the states of matter. square

Solution
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Answer

2Cr^{3+}(aq) + 6OH^{-}(aq) \rightarrow 2Cr(OH)_3(s) ### Ba^{2+}(aq) + SO_{4}^{2-}(aq) \rightarrow BaSO_4(s) Explanation 1. Identify reaction type This is a double displacement reaction where insoluble Cr(OH)_3 precipitates and BaSO_4 forms in solution. 2. Write balanced molecular equation Cr_{2}(SO_{4})_{3}(aq) + 3Ba(OH)_2(aq) \rightarrow 2Cr(OH)_3(s) + 3BaSO_4(s) 3. Write full ionic equation 2Cr^{3+}(aq) + 3SO_4^{2-}(aq) + 3Ba^{2+}(aq) + 6OH^{-}(aq) \rightarrow 2Cr(OH)_3(s) + 3BaSO_4(s) 4. Remove spectator ions SO_4^{2-} and Ba^{2+} form solid BaSO_4 directly, so no ions cancel in this precipitation. Both products insoluble, so net ionic contains both precipitation steps separately. 5. Write net ionic equation Separate into two precipitations: 1. 2Cr^{3+}(aq) + 6OH^{-}(aq) \rightarrow 2Cr(OH)_3(s) 2. Ba^{2+}(aq) + SO_{4}^{2-}(aq) \rightarrow BaSO_4(s)

Explanation

1. Identify reaction type <br /> This is a double displacement reaction where insoluble $Cr(OH)_3$ precipitates and $BaSO_4$ forms in solution. <br /><br />2. Write balanced molecular equation <br /> $Cr_{2}(SO_{4})_{3}(aq) + 3Ba(OH)_2(aq) \rightarrow 2Cr(OH)_3(s) + 3BaSO_4(s)$ <br /><br />3. Write full ionic equation <br /> $2Cr^{3+}(aq) + 3SO_4^{2-}(aq) + 3Ba^{2+}(aq) + 6OH^{-}(aq) \rightarrow 2Cr(OH)_3(s) + 3BaSO_4(s)$ <br /><br />4. Remove spectator ions <br /> $SO_4^{2-}$ and $Ba^{2+}$ form solid $BaSO_4$ directly, so no ions cancel in this precipitation. Both products insoluble, so net ionic contains both precipitation steps separately. <br /><br />5. Write net ionic equation <br /> Separate into two precipitations: <br />1. $2Cr^{3+}(aq) + 6OH^{-}(aq) \rightarrow 2Cr(OH)_3(s)$ <br />2. $Ba^{2+}(aq) + SO_{4}^{2-}(aq) \rightarrow BaSO_4(s)$
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