QuestionApril 19, 2025

For the chemical reaction Ca(s)+1/2O_(2)(g)arrow CaO(s)Delta H^circ =-635kJ/mol What is the molar enthalpy (inkJ/mol) for the reaction 2CaO(s)arrow 2Ca(s)+O_(2)(g)

For the chemical reaction Ca(s)+1/2O_(2)(g)arrow CaO(s)Delta H^circ =-635kJ/mol What is the molar enthalpy (inkJ/mol) for the reaction 2CaO(s)arrow 2Ca(s)+O_(2)(g)
For the chemical reaction Ca(s)+1/2O_(2)(g)arrow CaO(s)Delta H^circ =-635kJ/mol What is the molar enthalpy (inkJ/mol) for the reaction 2CaO(s)arrow 2Ca(s)+O_(2)(g)

Solution
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Answer

1270 kJ/mol Explanation 1. Identify the reverse reaction The given reaction is Ca(s) + \frac{1}{2}O_2(g) \rightarrow CaO(s) with \Delta H^\circ = -635 \text{ kJ/mol}. The reverse reaction is CaO(s) \rightarrow Ca(s) + \frac{1}{2}O_2(g). 2. Calculate enthalpy for reverse reaction Reverse the sign of \Delta H^\circ: \Delta H^\circ = 635 \text{ kJ/mol} for CaO(s) \rightarrow Ca(s) + \frac{1}{2}O_2(g). 3. Scale enthalpy for stoichiometry Multiply by 2 for 2CaO(s) \rightarrow 2Ca(s) + O_2(g): 2 \times 635 = 1270 \text{ kJ/mol}.

Explanation

1. Identify the reverse reaction<br /> The given reaction is $Ca(s) + \frac{1}{2}O_2(g) \rightarrow CaO(s)$ with $\Delta H^\circ = -635 \text{ kJ/mol}$. The reverse reaction is $CaO(s) \rightarrow Ca(s) + \frac{1}{2}O_2(g)$.<br /><br />2. Calculate enthalpy for reverse reaction<br /> Reverse the sign of $\Delta H^\circ$: $\Delta H^\circ = 635 \text{ kJ/mol}$ for $CaO(s) \rightarrow Ca(s) + \frac{1}{2}O_2(g)$.<br /><br />3. Scale enthalpy for stoichiometry<br /> Multiply by 2 for $2CaO(s) \rightarrow 2Ca(s) + O_2(g)$: $2 \times 635 = 1270 \text{ kJ/mol}$.
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